In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly distributed along the rod, with q=20.00 mC in the upper half and q=-20.00 mC in the lower half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field at P, the center of the semicircle fig.1 +g -9

In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly distributed along the rod, with q=20.00 mC in the upper half and q=-20.00 mC in the lower half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field at P, the center of the semicircle fig.1 +g -9

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 55P: The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly
distributed along the rod, with q = 20.00 mC in the upper half and q=-20.00 mC in the lower
half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis)
of the electric field at P, the center of the semicircle
fig.1
+q
P
-9

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