Use formula I provided plus don’t copy from chegg please explain me step by step would be very helpful to understand concept 6,7,8 6. A puck on a frictionless air hockey table has a mass of 0.5 kg and is attached to a cord passing through a hole in the surface as in the figure.The puck is revolving at a distance 2.0 m from the hole with an angular velocity of 0.40 rev/s. What is the kinetic energy of the puck? answer is 6.3 J 7.
Use formula I provided plus don’t copy from chegg please explain me step by step would be very helpful to understand concept 6,7,8 6. A puck on a frictionless air hockey table has a mass of 0.5 kg and is attached to a cord passing through a hole in the surface as in the figure.The puck is revolving at a distance 2.0 m from the hole with an angular velocity of 0.40 rev/s. What is the kinetic energy of the puck? answer is 6.3 J 7.
Use formula I provided plus don’t copy from chegg please explain me step by step would be very helpful to understand concept 6,7,8 6. A puck on a frictionless air hockey table has a mass of 0.5 kg and is attached to a cord passing through a hole in the surface as in the figure.The puck is revolving at a distance 2.0 m from the hole with an angular velocity of 0.40 rev/s. What is the kinetic energy of the puck? answer is 6.3 J 7.
Use formula I provided plus don’t copy from chegg please explain me step by step would be very helpful to understand concept 6,7,8
6. A puck on a frictionless air hockey table has a mass of 0.5 kg and is attached to a cord passing through a hole in the surface as in the figure.The puck is revolving at a distance 2.0 m from the hole with an angular velocity of 0.40 rev/s. What is the kinetic energy of the puck? answer is 6.3 J
7. A 2-kg object moving to the right with velocity 5 m/s collides with a 3-kg object which is initially at rest. After the collision, the 3-kg object has a velocity vector v = i – j. What is the speed of the 2-kg object after the collision? answer is 3.8m/s
8. If 15 J of potential energy are stored in a spring which has been compressed by 2 cm from its relaxed length, how much force will this spring exert if it is stretched by 4 cm from its relaxed length? answer is 3000n
Transcribed Image Text:The exam is closed book and closed notes.
v2
Circular motion: a =
W
Pavr =
At
Weight: Fg= mg,;
g = 9.8 m/s?;
Fnet = ma;
1
-m v²;
Potential energy: Ug = mgy
E = Er
E = U+K
Kinetic energy: K =
y2
- = o'r;
Rotational motion:
1 rev = 2n rad;
v = o r;
a αr;
a, =
r
r
1
@ = 00 + at;
0 = 0o t + -at2;
2θα -ω- ω02
K=-Io
T=r x F;
T=rFsino;
1
1
1
Icy= mR2
2
+ Rin
Στ-Ια;
Ipoint mass = mr?
Idisk =
mR
out
1
Ihoop = mR?
Irod(center) =
mL²
Irod(end)
mL²
2
Iball = =mR
12
Ishell =
mR?
I= Icom + MD?
1
K=.
1o,
1 Jo.?
work: W=t 0;
dW
P =
2
W=
2
P.
dt
Rolling:
2
-Io
1
m Vcom
Vcom = Ro
K =
2
T= f,R
Fs,max = HsFn
Incline: F= mgsin0 Fg mgcos0
Angular momentum:
Lpoint mass =m rxv
L= mrvsin 0;
L=m (r¡Vy - ryVx)k
L=Io
stae wil
LI = L
I 01 = I 202
m1X1+m2x2
X com =
mıy1+m2y2
m¡ +m2
Y com =
m1+m2
Definition Definition Rate of change of angular displacement. Angular velocity indicates how fast an object is rotating. It is a vector quantity and has both magnitude and direction. The magnitude of angular velocity is represented by the length of the vector and the direction of angular velocity is represented by the right-hand thumb rule. It is generally represented by ω.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.