Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In Figure 1, triangle \( \triangle ABC \) is a right triangle with a right angle at \( C \). The length of side \( BC \) is 15, and side \( AC \) is 3. We are asked to calculate \( \tan B \).
**Enter the exact answer.**
\[
\tan B = \quad \text{[Input Box]}
\]
**Explanation of Diagram:**
- **Triangle \( \triangle ABC \)**: A right triangle is illustrated, with a right angle indicated at point \( C \).
- **Sides**:
- \( BC = 15 \) (the side adjacent to angle \( B \))
- \( AC = 3 \) (the side opposite angle \( B \))
- **Angle \( B \)**: One of the non-right angles at point \( B \).
- The task is to calculate \( \tan B \), which is the ratio of the opposite side to the adjacent side for angle \( B \). Therefore, \( \tan B = \frac{AC}{BC} = \frac{3}{15} = \frac{1}{5} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F471cb0b1-24a7-4f47-a754-0c03ff5b6852%2F009233d4-9d33-48f1-a9ef-6e1e05441474%2Fi0vi7ii_processed.png&w=3840&q=75)
Transcribed Image Text:**Use Figure 1 to evaluate the trigonometric function.**
In Figure 1, triangle \( \triangle ABC \) is a right triangle with a right angle at \( C \). The length of side \( BC \) is 15, and side \( AC \) is 3. We are asked to calculate \( \tan B \).
**Enter the exact answer.**
\[
\tan B = \quad \text{[Input Box]}
\]
**Explanation of Diagram:**
- **Triangle \( \triangle ABC \)**: A right triangle is illustrated, with a right angle indicated at point \( C \).
- **Sides**:
- \( BC = 15 \) (the side adjacent to angle \( B \))
- \( AC = 3 \) (the side opposite angle \( B \))
- **Angle \( B \)**: One of the non-right angles at point \( B \).
- The task is to calculate \( \tan B \), which is the ratio of the opposite side to the adjacent side for angle \( B \). Therefore, \( \tan B = \frac{AC}{BC} = \frac{3}{15} = \frac{1}{5} \).
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