Use Euler's method with step size h = 0.1 to approximate the solution to the initial value problem y' = 3x - y², y(3) = 0, at the points x= 3.1, 3.2, 3.3, 3.4, and 3.5. The approximate solution to y'= 3x-y², y(3) = 0, at the point x = 3.1 is (Round to five decimal places as needed.) The approximate solution to y'= 3x - y², y(3) = 0, at the point x = 3.2 is (Round to five decimal places as needed.) The approximate solution to y'= 3x-y², y(3) = 0, at the point x = 3.3 is (Round to five decimal places as needed.) The approximate solution to y' = 3x - y², y(3) = 0, at the point x = 3.4 is (Round to five decimal places as needed.) The approximate solution to y'= 3x-y², y(3) = 0, at the point x = 3.5 is (Round to five decimal places as needed.) ←

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Using Euler's Method for Approximating Solutions of Differential Equations**

Euler's method with step size \( h = 0.1 \) is employed to approximate the solution to the initial value problem \( y' = 3x - y^2 \), \( y(3) = 0 \), at the points \( x = 3.1, 3.2, 3.3, 3.4, \) and \( 3.5 \).

---

**Approximation Steps:**

1. **At \( x = 3.1 \):**
   The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.1 \) is: 
   ```
   <input box>
   ```
   (Round to five decimal places as needed.)

2. **At \( x = 3.2 \):**
   The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.2 \) is: 
   ```
   <input box>
   ```
   (Round to five decimal places as needed.)

3. **At \( x = 3.3 \):**
   The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.3 \) is: 
   ```
   <input box>
   ```
   (Round to five decimal places as needed.)

4. **At \( x = 3.4 \):**
   The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.4 \) is: 
   ```
   <input box>
   ```
   (Round to five decimal places as needed.)

5. **At \( x = 3.5 \):**
   The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.5 \) is: 
   ```
   <input box>
   ```
   (Round to five decimal places as needed.)

---

This series of steps guides the user through applying Euler's method
Transcribed Image Text:**Using Euler's Method for Approximating Solutions of Differential Equations** Euler's method with step size \( h = 0.1 \) is employed to approximate the solution to the initial value problem \( y' = 3x - y^2 \), \( y(3) = 0 \), at the points \( x = 3.1, 3.2, 3.3, 3.4, \) and \( 3.5 \). --- **Approximation Steps:** 1. **At \( x = 3.1 \):** The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.1 \) is: ``` <input box> ``` (Round to five decimal places as needed.) 2. **At \( x = 3.2 \):** The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.2 \) is: ``` <input box> ``` (Round to five decimal places as needed.) 3. **At \( x = 3.3 \):** The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.3 \) is: ``` <input box> ``` (Round to five decimal places as needed.) 4. **At \( x = 3.4 \):** The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.4 \) is: ``` <input box> ``` (Round to five decimal places as needed.) 5. **At \( x = 3.5 \):** The approximate solution to \( y' = 3x - y^2 \), \( y(3) = 0 \), at the point \( x = 3.5 \) is: ``` <input box> ``` (Round to five decimal places as needed.) --- This series of steps guides the user through applying Euler's method
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