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Use Coulomb's law to find the magnitude of F23 (in N): 14211931 F23 = Ke Find the magnitude of the force F,3 (in N): 1411931 F13 Ke(vz a)? %3D Find the x- and y-components of the force F,3 (in N): F13x = (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = %3D !3! %3! Find the components of the resultant force (in N) acting on q3: N + (-1.94 N) Fax = F13x + F23x = F3y = F13y + F23y N +ON Express the resultant force (in N) acting on 9, in unit-vector form: F, ( i+ N Einalize The net force on n is unward and toward the left in the figure. If a. moves in response to the net force, the

Use Coulomb's law to find the magnitude of F23 (in N): 14211931 F23 = Ke Find the magnitude of the force F,3 (in N): 1411931 F13 Ke(vz a)? %3D Find the x- and y-components of the force F,3 (in N): F13x = (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = %3D !3! %3! Find the components of the resultant force (in N) acting on q3: N + (-1.94 N) Fax = F13x + F23x = F3y = F13y + F23y N +ON Express the resultant force (in N) acting on 9, in unit-vector form: F, ( i+ N Einalize The net force on n is unward and toward the left in the figure. If a. moves in response to the net force, the

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Use Coulomb's law to find the magnitude of F23 (in N): 192|1931 F23 = Ke a2 %3D Find the magnitude of the force F,3 (in N): 14,|1931 F13 = ke(z a)? Find the x- and y-components of the force F 13 (in N): F13x = (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = %3D N. %3D Find the components of the resultant force (in N) acting on q3: + F23x = N + (-1.94 N) F3x = F13x F3y = F13y + F23y %3D N + ON %3D %3D Express the resultant force (in N) acting on q3 in unit-vector form: F, - (_ 3) N î + %3D Finalize The net force on g, is upward and toward the left in the figure. If q3 moves in response to the net force, the distances between q, and the other charges change, so the net force changes. Therefore, if q, is free to move, it can be modeled as a particle ---Select--- e as long as it is recognized that the force exerted on q3 is not constant. EXERCISE
Transcribed Image Text:Use Coulomb's law to find the magnitude of F23 (in N): 192|1931 F23 = Ke a2 %3D Find the magnitude of the force F,3 (in N): 14,|1931 F13 = ke(z a)? Find the x- and y-components of the force F 13 (in N): F13x = (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = %3D N. %3D Find the components of the resultant force (in N) acting on q3: + F23x = N + (-1.94 N) F3x = F13x F3y = F13y + F23y %3D N + ON %3D %3D Express the resultant force (in N) acting on q3 in unit-vector form: F, - (_ 3) N î + %3D Finalize The net force on g, is upward and toward the left in the figure. If q3 moves in response to the net force, the distances between q, and the other charges change, so the net force changes. Therefore, if q, is free to move, it can be modeled as a particle ---Select--- e as long as it is recognized that the force exerted on q3 is not constant. EXERCISE
Find the Resultant Force Consider three point charges located at the corners of a right triangle as shown in the figure, where q, = 93 = 3.50 µC, q2 = -2.00 µC, and a 0.180 m. Find the resultant force exerted on q3. %3D %3D %3D %3D The force exerted by q, on 9, s F13' is The force 4) exerted by q2 on q3 is F,3: The resultant force F, is the vector sum F 13 + F 23' す。 F1s a 23 92 93 a VZa 41+ SOLUTION Conceptualize Think about the net force on q3. Because charge qa is near two other charges, it will experience two electric forces. These forces are exerted in different directions as shown in the figure. Based on the forces shown in the figure, estimate the direction of the net force vector. O directly towards the left directly towards the right towards the right and downward towards the left and upward Categorize Because two forces are exerted on charge q3, we categorize this example as a vector ---Select--- problem. Analyze The directions of the individual forces exerted by q, and q, on q3 are shown in the figure. The force F,3 exerted by q, on 93 is ---Select--- 9because have opposite signs. In the coordinate system shown in the figure, the force F23 is to the left (in the negative x-direction). 92 and 93 The force F,3 exerted by q, on q is ---Select--- ebecause both charges are positive. The force F. 13 makes an angle of 45.0° with the x-axis.
Transcribed Image Text:Find the Resultant Force Consider three point charges located at the corners of a right triangle as shown in the figure, where q, = 93 = 3.50 µC, q2 = -2.00 µC, and a 0.180 m. Find the resultant force exerted on q3. %3D %3D %3D %3D The force exerted by q, on 9, s F13' is The force 4) exerted by q2 on q3 is F,3: The resultant force F, is the vector sum F 13 + F 23' す。 F1s a 23 92 93 a VZa 41+ SOLUTION Conceptualize Think about the net force on q3. Because charge qa is near two other charges, it will experience two electric forces. These forces are exerted in different directions as shown in the figure. Based on the forces shown in the figure, estimate the direction of the net force vector. O directly towards the left directly towards the right towards the right and downward towards the left and upward Categorize Because two forces are exerted on charge q3, we categorize this example as a vector ---Select--- problem. Analyze The directions of the individual forces exerted by q, and q, on q3 are shown in the figure. The force F,3 exerted by q, on 93 is ---Select--- 9because have opposite signs. In the coordinate system shown in the figure, the force F23 is to the left (in the negative x-direction). 92 and 93 The force F,3 exerted by q, on q is ---Select--- ebecause both charges are positive. The force F. 13 makes an angle of 45.0° with the x-axis.
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