(b)Use Bernoulli's energy balance equation (E = PV + 0.5*mU²), assume volume flow rate remainsconstant along the pipe such that (Q=UA), and assume that pressure is balanced manometer toperform the following derivations:(i)(ii)(iii)1- P2 in the pipe (substitute U2 in this step).an expression for P₁an expression for P₁P2 in the U-tube manometer.Set the expressions in parts (i) and (ii) equal to one another and derive the flow equation:U₁ =2 (Pm -1) ghBA- 1

Answered: Image /qna-images/answer/c18da311-fc90-49ba-9deb-f4e3575188a2.jpg

Use Bernoulli's energy balance equation (E = PV + 0.5*mU2), assume volume flow rate remains constant along the pipe such that (Q=UA), and assume that pressure is balanced manometer to perform the following derivations: (ii) (iii) an expression for P₁ P2 in the pipe (substitute U₂ in this step). an expression for P₁ P2 in the U-tube manometer. Set the expressions in parts (i) and (ii) equal to one another and derive the flow equation: U₁ = 2 (Pm - 1) gh NN-N - 1

Use Bernoulli's energy balance equation (E = PV + 0.5*mU2), assume volume flow rate remains constant along the pipe such that (Q=UA), and assume that pressure is balanced manometer to perform the following derivations: (ii) (iii) an expression for P₁ P2 in the pipe (substitute U₂ in this step). an expression for P₁ P2 in the U-tube manometer. Set the expressions in parts (i) and (ii) equal to one another and derive the flow equation: U₁ = 2 (Pm - 1) gh NN-N - 1

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: U - tube is used to pressure the difference in water channel. p1= 1000 kg/m3. The orange fluid in…

A: Water density = 1000 kg/m3 Orange fluid = 2000 kg/m3 Pressure at point 1 = 111 kpa a = 10 cm h = 15…

Q: 2. Oil with a S.G. pf 0.82 is flowing in a pipe under the condition below (see figure). If the total…

A: Given data as per the question The specific gravity of oil =0.82 Total head loss =3 ft Q =2.08 cfs…

Q: 1. A hydraulic pump is shown in Figure 1, flow rate is 25 L/min, the diameter of suction pipe is…

A: Given Data Flow rate, =25 L/min Diameter of suction pipe, =25 mm Suction port of pump is higher…

Q: 2. Oil (sg=0.90) is flowing at 150 L/min through a turbine. The pressure before the turbine is 750…

A: The flow rate of oil is Q=150 l/min. The specific density is SG=0.9. The pressure before the turbine…

Q: Q2/ Consider the following liquid level system shown below. The flow through the valve is related to…

A: Given Data:Find:Relationship between the head and time.

Q: The characteristics for a pump are given in the table below. The pump is required to left water…

Q: 15. Hydraulic oil with a Sg of 0.91 is pumped horizontally in a 2-in. I.D. distribution line at the…

Q: (b) A venturi meter with diameter at inlet D, and throat diameter D2, is used for measuring the flow…

Q: Question 4 A sprinkler system pumps water through a large pipe inlet with a diameter (d₁). The pipe…

A: (a) To find: The expression for velocity of water leaving the sprinkler. Given: The inlet diameter…

Q: Water in a vertical (i.e., gravitational force of the fluid in the nozzle plays a role, and the…

Q: A linear (laminar) averagewall shear stress resistance of the form τ ≈ 8 μ V/D , whereμ is the fl…

A: Break the given figure into two moving control volumes one for each leg. Here, CV1 and CV2…

Q: Consider 2 which shows a pipe system connecting two reservoirs. The pipe diameter changes at point B…

A: Given : The pipe friction coefficient is f=0.005 The coefficient of contraction is kL=0.6 Length of…

Concept explainers

Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

Question

(b)
Use Bernoulli's energy balance equation (E = PV + 0.5*mU²), assume volume flow rate remains
constant along the pipe such that (Q=UA), and assume that pressure is balanced manometer to
perform the following derivations:
(i)
(ii)
(iii)
1- P2 in the pipe (substitute U2 in this step).
an expression for P₁
an expression for P₁
P2 in the U-tube manometer.
Set the expressions in parts (i) and (ii) equal to one another and derive the flow equation:
U₁ =
2 (Pm -1) gh
BA
- 1

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Please fast
Q2/: As shown in the figure, the Assumptions of the flow through the venturi is steady, incompressible, irrational with negligible frictional effects , the effect of air column on the pressure change is negligible, the pressure can be assumed to be uniform at a given cross-section of the venturi meter and the flow is horizontal . Air is flowing through a venturi meter whose diameter is 2.6 in at the entrance part (location 1) and 1.8 in at the throat (location 2). The gage pressure is measured to be 12.2 psia at the entrance and 11.8 psia at the throat. Neglecting frictional effects, take the air density to be 0.075 lbm/ft. 1. Show that the volume flow rate can be expressed as: 2(P P2) | = A, p(1 – AŽIA}) 2. Find the flow rate of the air? 12.2 psia 11.8 psia Air 2.6 in 1.8 in
The following figure shows a bent in a pipe with a diameter of D (cm). Pressure is measured in cross section#1 as demonstrated in the figure as P1 (kPa). In cross section#2 the diameter reduced through a nozzle to 5.0 cm and the water is discharged into atmosphere. The elevation difference between two cross sections is 0.5 m. Assume all losses are negligible and density of the fluid, water, is 1000 kg/m³. a) Find the velocity in cross section#1; b) Calculate the horizontal and vertical forced acting on the pipe and the direction of the resultant force. D = 20 cm, Pj= 450 kPa Cross section#2 0.5 m Diameter: 5 cm P1 60° Cross section#1 Diameter: D cm
Water enters a fountain through a pipe with a cross-sectional area A₁ at a flowrate Q. The pressure in the inlet pipe is p₁. The water then leaves through a nozzle with a cross- sectional area A2 and at an angle 0, as shown in Figure Q5. Both the inlet and the nozzle are at a height h2, and the jet reaches a maximum height h3. X You may assume that viscosity is negligible. a) Find the horizontal force on the block b) What is the horizontal-component (u₂), vertical component (v₂) and magnitude (V₂) of the velocity of the jet as it leaves the nozzle? = c) What is the maximum height of the jet? You may assume that the horiztonal component of velocity is the same at every point in the jet.
7. Blood is flowing through point P (Figure 2.5), which is connected to a catheter tip manometer system. Blood enters the manometer and equilibrates the pressure of the various fluids within the system (as denoted in the figure). Calculate the pressure within the blood vessel. Blood density is 1050 kg/m³, atmospheric pressure is 760 mmHg 25 cm Blood Fluid 1, P₁ = 879 kg/m³ Ja 45 cm 2 1 10 cm ✓ Fluid 2. P2 = 1200 kg/m³ Atmospheric pressure Figure 2.5 Schematic of a catheter tip manometer to measure intravascular blood pressure
Q(in) is a constant inflow which maintains the water level in the tank. Find the horizontal force needed to hold the tank stationary. If you could make any notes on steps in the method to make it clearer that would be great too. Thanks in advance!
I want you to draw the HGL and EGL using the second picture.
Energy Equation Problem
2. A turbine is used to produce 2700 hp by expanding the water between points 1 and 2. Water flow rate, static pressures and pipe diameters are given. Calculate the power lost in between point one and two. Note that the static pressure at point 2 is given in vacuum. (SGH =13.6) P1 = 60 psi Q = 150 ft³/s D = 3 ft Section (1) Turbine 10 ft P2 10-in. Hg %3D vacuum D2 = 4 ft Section (2)
Example: What is the pressure at the center of the pipe B?
Water enters a fountain through a pipe with a cross-sectional area A₁ at a flowrate Q. The pressure in the inlet pipe is p₁. The water then leaves through a nozzle with a cross- sectional area A₂ and at an angle 0, as shown in Figure Q5. Both the inlet and the nozzle are at a height h₂, and the jet reaches a maximum height h3. You may assume that viscosity is negligible. a) Find the horizontal force on the block b) What is the horizontal-component (u₂), vertical component (v₂) and magnitude (V₂) of the velocity of the jet as it leaves the nozzle? c) What is the maximum height of the jet? You may assume that the horiztonal component of velocity is the same at every point in the jet. P₁ A₂. Ө h₂ h3 Figure Q5: Jet emitting from a fountain.
Find the horizontal and vertical forces to hold stationary the nozzle shown in the figure below. The fluid flowing through it is 10 °C liquid water; A₁ = 1.2 m², A₂ = 0.300 m², V₁ = 15 m/s, p2 = Patm and p₁ = Patm + 75 kPa. Neglect effects of gravity. Fx= i Fy= i A1 P1 KN kN Fy ZA A2, P2 = Patm Fx 45° Patm