problem is attached!i need to see all steps in correct order please. i have a few more problems like this so i want to make sure i understand how to solve this problem.please and thank you so much! Use an inverse to solve the equation. Show all steps. Upload your written work to thisproblem. Your answer will include the letter A. Give all solutions in general form.V2 sin 0) = A

The given equation is, 2sin23θ=ASo,from the given equation we have, 2sin23θ=ANow, divide both sides of the equation with 2 to make your given function coeffient free, all we have to do for this type of problems is just make the given function coefficient free.⇒sin23θ=A2Now, multipling both sides of the equation with sin-1⇒ sin-1sin23θ=sin-1A2As we know sin-1(sinx)=x,so we have, ⇒23θ=sin-1A2 Multipling both sides of the equation with 32⇒θ=32sin-1A2We can write the solutions as, θ1=180+32sin-1A2 and θ2=360-32sin-1A2 We know sine and cosine functions are periodic with period of 360 degree. So, the general solution can be written as, θ1=180+32sin-1A2+n(360) and θ2=360-32sin-1A2+n(360)Where n=1,2,3,... ANSWER: The inverse problem is, θ=32sin-1A2 The general solution is, θ1=180+32sin-1A2+n(360) and θ2=360-32sin-1A2+n(360)Where, n=1,2,3,...