Use a Maclaurin series in the table below to obtain the Maclaurin series for the given function. f(x) = 8ex + eбx M8 00 n=0 x = Σ= 1 + +. R = 1 11-0 x = 1+ n-on! 00 sin x (-1)" - -0 1! 21 31 x2m+1 (2n+1)! =x- + x 5! R = 00 - R = 00 Σ(-1)* x2m cos x=(-1)". = 1 21 4! 11-0 tan-x=(-1)* -0 00 k (2n)! x-2n+1 2n+1 =x - 6! - R = 00 R=1 5 k(k-1) k(k-1)(k-2) = 1 + kx + R=1 2! 3! (1 + x)* = (^)x*= Σ 11-0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use a Maclaurin series in the table below to obtain the Maclaurin series for the given function.
f(x) = 8ex + eбx
M8
00
n=0
x
=
Σ= 1 +
+.
R = 1
11-0
x
= 1+
n-on!
00
sin x (-1)"
-
-0
1! 21 31
x2m+1
(2n+1)!
=x-
+
x
5!
R = 00
-
R = 00
Σ(-1)*
x2m
cos x=(-1)".
= 1
21
4!
11-0
tan-x=(-1)*
-0
00
k
(2n)!
x-2n+1
2n+1
=x
-
6!
-
R = 00
R=1
5
k(k-1)
k(k-1)(k-2)
= 1 + kx +
R=1
2!
3!
(1 + x)* = (^)x*=
Σ
11-0
Transcribed Image Text:Use a Maclaurin series in the table below to obtain the Maclaurin series for the given function. f(x) = 8ex + eбx M8 00 n=0 x = Σ= 1 + +. R = 1 11-0 x = 1+ n-on! 00 sin x (-1)" - -0 1! 21 31 x2m+1 (2n+1)! =x- + x 5! R = 00 - R = 00 Σ(-1)* x2m cos x=(-1)". = 1 21 4! 11-0 tan-x=(-1)* -0 00 k (2n)! x-2n+1 2n+1 =x - 6! - R = 00 R=1 5 k(k-1) k(k-1)(k-2) = 1 + kx + R=1 2! 3! (1 + x)* = (^)x*= Σ 11-0
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