Use a calculator. n the first field on the left, type: v =[0, 2.6, 3, 3.7, 4.5, 4.5, 5.9, 6.3, 6.5, 7, 8] What is the IQR? Q3-Q1 from the box plot. Type: boxplot(v, 2) into the second field. Adjust height to 3. Find the Q3 and Q1. Find IQR.
Use a calculator.
n the first field on the left, type: v =[0, 2.6, 3, 3.7, 4.5, 4.5, 5.9, 6.3, 6.5, 7, 8]
What is the IQR? Q3-Q1 from the box plot.
Type: boxplot(v, 2) into the second field.
Adjust height to 3. Find the Q3 and Q1. Find IQR.
Since it is not mention which calculater to use I will solve the first part for you manually.
The boxplot displays the five - summary of data. The five - number summary is the minimum value, 1st Quartile ( Q1) , Median, 3rd Quartile and the maximum value.
Data : v =[0, 2.6, 3, 3.7, 4.5, 4.5, 5.9, 6.3, 6.5, 7, 8]
The 5- summary statistics:
Minimum value =
Maximum value =
To find Median below are the steps -
- Arrange the data in ascending order ( from lowest to the highest value ). We can see that data is already aranged in ascending order.
- Count the total number of observation. The total number of observations are 11 there is odd number of terms, the median is the center term or it can found using formula.
Q1 : The median is 4.5 consider all the data values which are below the 4.5 which are [0,2.6,3,3.7, 4.5]. These observations will be called the "first half of data". In the first half there are 5 observations which is again odd. Therefore the median of the first half of data is as given by.
Therefore the first quartile (Q1) = 3
Q3: Similarly we can find the Q3 but now we have to consider the data which are above the 4.5 which are [5.9,6.3,6.5,7,8]. These observations will be called the "second half of data". In the second half there ae 5 observations which is odd. Therefore , the median of the second half of data is given by.
Therefore the first quartile (Q3) = 6.5
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