The types of browse favored by deer are shown in the following table. Using binoculars, volunteers observed the feeding habits of a random sample of 320 deer.Plant Compositionin Study AreaObserved Number of DeerType of BrowseSage brushRabbit brushFeeding on This Plant9013832%38.7%12%Salt brush43Service berry9.3%8%24Other25A USE SALTUse a 5% level of significance to test the claim that the natural distribution of browse fits the deer feeding pattern.(a) What is the level of significance?State the null and alternate hypotheses.O H: The distributions are the same.H,: The distributions are the same.O H: The distributions are different.The distributions are the same.O H: The distributions are different.The distributions are different.O Ho: The distributions are the same.H: The distributions are different.(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)Are all the expected frequencies greater than 5?O YesO NoWhat sampling distribution will you use?O chi-squareO Student'stO normalbinomialO uniformWhat are the degrees of freedom? Are all the expected frequencies greater than 5?O YesNoWhat sampling distribution will you use?O chi-squareO Student'stO normalO binomialO uniformWhat are the degrees of freedom?(c) Estimate the P-value of the sample test statistic.O P-value > 0.100O 0.050 < P-value < 0.100O 0.025 < P-value < 0,050O 0.010 < P-value < 0.025O 0.005 < P-value < 0.010O P-value < 0.005(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?O Since the P-value > a, we fail to reject the null hypothesis.O Since the P-value > a, we reject the null hypothesis.O Since the P-value < a, we reject the null hypothesis.O Since the P-value < a, we fail to reject the null hypothesis.(e) Interpret your conclusion in the context of the application.O At the 5% level of significance, the evidence is sufficient to conclude that the natural distribution of browse does not fit the feeding pattern.O At the 5% level of significance, the evidence is insufficient to conclude that the natural distribution of browse does not fit the feeding pattern.

Test is that whether the natural distribution of browse fits the deer feeding pattern. Note :…

Answered: Use a 5% level of significance to test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The critical value in a hypothesis test Multiple Choice depends on the value of the test statistic. is calculated from the sample data. separates the acceptance and rejection regions. usually is .05 or .01 in most statistical tests.
K The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. D iew an example Get more help. 42 W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps J D. Ho: -5.00 Mbps H₁: - Clear all : - ; X option F11 { [ ? + = 1 I Check answer F12 } ] delete retu
11:39 1 A myopenmath.com You are conducting a multinomial hypothesis test (a = 0.05) for the claim that all 5 categories are equally likely to be selected. Complete the table. Observed Expected Category Frequency Frequency A 13 В 11 C 12 17 E 23 Report all answers accurate to three decimal places. But retain unrounded numbers for future calculations. What is the chi-square test-statistic for this data? (Report answer accurate to three decimal places, and remember to use the unrounded Pearson residuals in your calculations.) What are the degrees of freedom for this test? d.f.= What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a
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A recent study investigated if the distribution of gender is the same across all academic ranks. Data were collected by taking a random sample of individuals from within each academic rank and then recording each individuals gender. Use the output below to conduct the appropriate hypothesis test. Use a 0.05 level of significance. Null and alternative hypotheses Test Statistic value p-value decision based on the p-value
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A preliminary study regarding the number of AIDS cases reported for Santa Clara County, California is broken down by race in the table below. White Hispanic Black Asian/Pacific Islander TOTAL Race White Hispanic Black Conduct a chi-square test for goodness-of-fit to determine whether or not the occurrence of AIDS cases is consistent with the race distribution of Santa Clara County. Cases Choose the correct null and alternative hypotheses: O Ho: The distribution of AIDS cases is different from the race distribution in Santa Clara County. Ha: The distribution of AIDS cases is consistent with the race distribution in Santa Clara County. TOTAL 22 Ho: The distribution of AIDS cases is consistent with the race distribution in Santa Clara County. Ha : The distribution of AIDS cases is different from the race distribution in Santa Clara County. Race Asian/Pacific Islander 14 ▼ Part 2 of 4 The population distribution of Santa Clara County by race is provided in the table below. Use these…
A p-value smaller than the significance level, a means.... We should reject the Null Hypothesis O We should not reject the Null Hypothesis

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