Use a 0.05 level of significance to test the claim that the mean cost of a taxicab ride in New York City is less than $15.00. A random sample of 40 taxi fares resulted in a mean of $12.04 and a standard deviation of $8.36.
Q: Recent Environmental Protection Agency (EPA) fuel economy estimates for automobile models tested…
A: Given that Mean(µ) = 24.8 Standard deviations (σ) = 6.2
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Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…
A: Given information- Population mean, μ = $53 Sample size, n = 100 Sample mean, x-bar = $60 Sample…
Q: hypothesis? Null Hypothesis f. What is the test statistic for the given statistics? g. What is the…
A: Given that Sample size n =39 Sample mean =616.9 Standard deviation =51.6
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A: Given that,Dougall compared the resting heart rate of average healthy citizens and soldiers…
Q: Suppose that the number of hours that an adult watches in a day has a mean of 2.4 hours and a…
A: Given: Mean, μ=2.4 hours Standard deviation, σ=0.7 hours (i) Percentage of adults watch between 1…
Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…
A: The summary of statistics is,
Q: For a study conducted by the research department of a pharmaceutical company, 225 randomly selected…
A: It was stated that a study was conducted on a pharmaceutical company by the research department. A…
Q: The carbon dioxide emissions of EU nations had a mean of 7.9 and standard deviation of 3.6. a.…
A: Since we have given that Mean(µ) = 7.9Standard deviations (σ) = 3.6 Since part (a) you have already…
Q: If gasoline in a certain part of the country has a mean price of $1.62 per gallon and a standard…
A: From the given information, Mean = $1.62 gallon Standard deviation =8 cents =$0.08 gallon (since 100…
Q: Suppose that the distribution of income in a certain tax bracket is approximately normal with a mean…
A: Probability distribution: A probability distribution function is the statistical function that…
Q: An article presents a study of health outcomes in women with symptoms of heart disease. In a sample…
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Q: A company finds that for its 12 ounce cans of soda, the actual amount of soda inside is Normally…
A: Solution-: Given: μ=12,σ=0.25 We find x value such that P[X<x]=0.15
Q: Steve believes that his wife’s cell phone battery does not last as long as his cell phone battery.…
A: From the given information,
Q: A market research firm reported that the mean annual earnings of all family practitioners in the…
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Q: A local supermarket spent $250,000 remodeling. Prior to remodeling, the average daily receipts were…
A: From the provided information, Sample size (n) = 18 Sample mean (x̅) = $59800 Standard deviation (s)…
Q: Full-time college students report spending a mean of 29 hours per week on academic activities, both…
A: Givenmean(μ)=29standard deviation(σ)=4sample size(n)=64
Q: Airline companies are interested in the consistency of the number of babies on each flight, so that…
A: Test for Variance: The χ2 Chi-Square test is used to test the significance difference between…
Q: Suppose the average golfer drives the ball around 259.1 yards with a standard deviation of 9.73.…
A: Solution
Q: A marketing researcher wants to estimate the mean amount spent per year (5) on a web site by…
A: Given information Hypothesized mean µ = $49 Sample size (n) = 130 Mean x̅ = $55 Standard deviation…
Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…
A: Let, X = Amount spent per year ($) on a web site by membership member shoppers. Given that;…
Q: For a study conducted by the research department of a pharmaceutical company, 265 randomly selected…
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Q: Consider a data set that has a mean of 15.5 and a standard deviation of 6.2. According to…
A: Given: Mean = 15.5 Standard deviation = 6.2 First of all, we find k It is given that 93.75% of the…
Q: Steve believes that his wife’s cell phone battery does not last as long as his cell phone battery.…
A: Method By using the 90% confidence level to construct a confidence interval.
Q: recent survey compared the costs of adoption through public and private agencies. For a sample of 16…
A: Solution: Given information: n1=16 Sample size of public agency n2= 18 Sample size of private…
Q: According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or…
A: The number of sampled bottles, n=58.The hypothesized average price of the bottles with scores of 4.0…
Q: For a study conducted by the research department of a pharmaceutical company, 205 randomly selected…
A: Given Sample size n1=205, sample mean x̄1=17.6, s1=sample standard deviations=5.3, n2=sample size…
Q: The mean annual tuition and fees for a sample of 15 private colleges was $41,200 with a standard…
A: Given: n=15x¯=41200s=5300μ=38000α=0.05 The test hypothesis are, H0: μ=38000H1: μ≠38000. This is a…
Q: State the conclusion in the problem context. We fail to reject H0. It is not reasonable to…
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Q: The number of chocolate chips in a popular brand of cookie is normally distributed with a mean of 22…
A: given data normal distribution μ = 22 chocolate chips per cookieσ = 3.1 chocolate chips per cookie…
Q: parenting magazine reports that the average amount of wireless data used by teenagers each month is…
A: To test Ella's claim, we can perform a one-sample t-test. Here are the steps involved: Step 1:…
Q: The salary for workers at a company are normally distributed with a mean of $60,000 and a standard…
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Q: An automotive engineer believes that her newly designed engine will be a great gas saver. A large…
A: Population mean (µ) = 27.5Standard deviations (σ) = 5.2Sample size (n) = 15Sample mean (x̅) = 29.6…
Q: The Iowa Department of Transportation repaired hundreds of bridges in 1993. To check the average…
A: Step 1: List the given values. We are given the following: population mean cost to repair a bridge,…
Q: aking the family to an amusement park has become ncreasingly costly according to the industry…
A: We have given that, Sample mean (x̄) = $ 232, sample standard deviation (s) = 42 and sample size…
Q: A quick survey of peanut butter prices had standard deviation and mean of $0.26 and $3.68,…
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Q: A study was conducted to assess the effects that occur when children are exposed to cocaine before…
A: Given, n1 = 182 , x1 = 7.4 , s12 = 2.9n2 = 181 , x2 = 8.4 , s22 = 3.1 Degree of freedom,…
Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…
A: Given values, n=100x¯=60s=55
Use a 0.05 level of significance to test the claim that the
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- Automobile collision insurance is used to pay for any claims made against the driver in the event of an accident. This type of insurance will typically pay to repair any assets that your vehicle damages. A random sample of 40 collision claims of 20- to 24-year-old drivers results in a mean claim of $4580 with a standard deviation of $2291. An independent random sample of 40 collision claims of 30- to 59-year-old drivers results in a mean claim of $3680 with a standard deviation $2036. Using the concept of hypothesis testing, determine if a higher insurance premium should be paid by 20- to 24-year-old drivers. Use a a = 0.10 level of significance, and let population 1 be 20- to 24-year old drivers and population 2 be 30- to 59-year old drivers. Complete pa through (e) below. (a) Collision claims tend to be skewed right. Why do you think this is the case? O A. There are many large collision claims relative to the majority of claims.For a study conducted by the research department of a pharmaceutical company, 235 randomly selected individuals were asked to report the amount of money they spend annually on prescription allergy relief medication. The sample mean was found to be $17.80 with a standard deviation of $4.30 . A random sample of 250 individuals was selected independently of the first sample. These individuals reported their annual spending on non-prescription allergy relief medication. The mean of the second sample was found to be $18.20 with a standard deviation of $4.00 . As the sample sizes were quite large, it was assumed that the respective population standard deviations of the spending for prescription and non-prescription allergy relief medication could be estimated as the respective sample standard deviation values given above. Construct a 90% confidence interval for the difference −μ1μ2 between the mean spending on prescription allergy relief medication ( μ1 ) and the mean…Statewide, the population as a whole watches 6.2 hours of TV per day. A random sample of 1017 senior citizens in the state reports watching an average of 5.9 hours per day, with a standard deviation of 0.7. is the difference significant
- The average waiting time in a doctor’s office varies. The standard deviation of waiting times in a doctor’s office is 3.4 minutes. A random sample of 30 patients in the doctor’s office has a standard deviation of waiting times of 4.1 minutes. One doctor believes the variance of waiting times is greater than originally thought.a. What type of test should be used?b. What is the test statistic?c. What is the p-value?d. What can you conclude at the 5% significance level?A hospital president claims that the average Salary of registered nurses at her hospital is more than $57,000. You test this claim by surveying 37 registered nurses at this hospital and find they have a mean salary of $57,425. Assume the population standard deviation is $1750 at the 0.10 level of significance is there enough evidence to support the claim of the hospital president?The America Automobile Association reported that the mean price of a gallon of regular grade gasoline in the United States in October 2020 was $2.82. An economist is interested in determining whether the mean price of regular grade gasoline is cheaper (less than) in New York State. To test this, the economist sample 50 gas stations in NY and find the mean price of regular grade gasoline to be $2.77. Assume the standard deviation for the price of regular grade gasoline is $0.15. Use the critical value method to perform a hypothesis test at the 0.05 level of significance. a) what is the conclusion for this test?
- Steve believes that his wife's cell phone battery does not last as long as his cell phone battery. On eleven different occasions, he measured the length of time his cell phone battery lasted and calculated that the mean was 16.4 hours with a standard deviation of 6.4 hours. He measured the length of time his wife's cell phone battery lasted on seven different occasions and calculated a mean of 23.3 hours with a standard deviation of 4.2 hours. Assume that the population variances are the same. Let Population 1 be the battery life of Steve's cell phone and Population 2 be the battery life of his wife's cell phone. Step 1 of 2: Construct a 90 % confidence interval for the true difference in mean battery life between Steve's cell phone and his wife's. Round the endpoints of the interval to one decimal place, if necessary.An employer claims that full time employees have a mean income of $35,000. A sample of 200 employees was considered. Their mean salary was $34,000. Assuming a population standard deviation of $4,000. Does her claim seem reasonable at a 0.05 level of significance?Average adult Americans are about one inch taller but nearly a whopping 25 pounds heavier than they were in 1960, according to a report from the Centers for Disease Control and Prevention (CDC). City A is considered one of America's healthiest cities. Is the weight gain since 1960 similar in city A? A sample of n=25 adults suggested a mean increase of 22 pounds with a standard deviation of 9.4 pounds. Is City A significantly different in terms of weight gain since 1960? Complete and interpret 5 step hypothesis testing by hand at a 5% level of significance using a Z-test. Show each step and your work.
- A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by membership member shoppers. Suppose a random sample of 100 membership member shoppers who recently made a purchase on the web site yielded a mean amount spent of $55 and a standard deviation of $52. Complete parts (a) and (b) below. a. Is there evidence that the population mean amount spent per year on the web site by membership member shoppers is different from $51? (Use a 0.01 level of significance.) State the null and alternative hypotheses. Ho: H (Type integers or decimals. Do not round. Do not include the $ symbol in your answer.) Identify the critical value(s). The critical value(s) is/are (Type an integer or a decimal. Round to two decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic. The test statistic, 1STAT, is (Type an integer or a decimal. Round to two decimal places as needed.) State the conclusion. Ho. There is evidence that the…The America Automobile Association reported that the mean price of a gallon of regular grade gasoline in the United States in October 2020 was $2.82. An economist is interested in determining whether the mean price of regular grade gasoline is cheaper (less than) in New York State. To test this, the economist sample 50 gas stations in NY and find the mean price of regular grade gasoline to be $2.77. Assume the standard deviation for the price of regular grade gasoline is $0.15. Use the critical value method to perform a hypothesis test at the 0.05 level of significance. a. Define the parameter we are testing and setup a hypothesis test to see if the mean price of gas is cheaper in NY compared to the national mean: b. Calculate the test statistics for this hypothesis test. c.What is the critical value for this hypothesis test?According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 64 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. (a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for # as needed.) Ho: H: (b) Using the sample from the 64 bottles, what is the test statistic? (Round your answer to three decimal places.) Using the sample from the 64 bottles, what is the p-value? (Round your answer to four decimal places.) p-value =…
