Uranium-238 is the most commonly occurring isotope of uranium. i. A possible fission is given by the disintegration equation: 232U¹4La +3Br + 3n. → Show that about 160 MeV of kinetic energy is released given the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La and 90 Br, respectively, the neutron mass of 939.6 MeV/c² and t = 931.5 MeV/c2.
Uranium-238 is the most commonly occurring isotope of uranium. i. A possible fission is given by the disintegration equation: 232U¹4La +3Br + 3n. → Show that about 160 MeV of kinetic energy is released given the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La and 90 Br, respectively, the neutron mass of 939.6 MeV/c² and t = 931.5 MeV/c2.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![Uranium-238 is the most commonly occurring isotope of uranium.
i. A possible fission is given by the disintegration equation:
90
238
92
U→ 145La +3Br +3n.
57
Show that about 160 MeV of kinetic energy is released given
the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La
and 90Br, respectively, the neutron mass of 939.6 MeV/c² and
u =931.5 MeV/c2.
ii. A second decay path is through alpha decay:
238 U →
234Th + a.
92
90
By comparing formulas, show that the Coulomb barrier for the
fission process is over 8 times higher than that for the alpha pro-
cess.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F874107fb-633b-4094-9f9e-2f06b7fe2b7b%2F313333f8-0666-425a-a6fc-d3323cc760c7%2Fqtjm2c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Uranium-238 is the most commonly occurring isotope of uranium.
i. A possible fission is given by the disintegration equation:
90
238
92
U→ 145La +3Br +3n.
57
Show that about 160 MeV of kinetic energy is released given
the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La
and 90Br, respectively, the neutron mass of 939.6 MeV/c² and
u =931.5 MeV/c2.
ii. A second decay path is through alpha decay:
238 U →
234Th + a.
92
90
By comparing formulas, show that the Coulomb barrier for the
fission process is over 8 times higher than that for the alpha pro-
cess.
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didnt asnwer part ii, please asnwer part ii
![Uranium-238 is the most commonly occurring isotope of uranium.
i. A possible fission is given by the disintegration equation:
90
238
92
U→ 145La +3Br +3n.
57
Show that about 160 MeV of kinetic energy is released given
the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La
and 90Br, respectively, the neutron mass of 939.6 MeV/c² and
u =931.5 MeV/c2.
ii. A second decay path is through alpha decay:
238 U →
234Th + a.
92
90
By comparing formulas, show that the Coulomb barrier for the
fission process is over 8 times higher than that for the alpha pro-
cess.](https://content.bartleby.com/qna-images/question/874107fb-633b-4094-9f9e-2f06b7fe2b7b/8e93c0fc-6616-4a26-98c1-bd99a26d8a2c/8boynm_thumbnail.jpeg)
Transcribed Image Text:Uranium-238 is the most commonly occurring isotope of uranium.
i. A possible fission is given by the disintegration equation:
90
238
92
U→ 145La +3Br +3n.
57
Show that about 160 MeV of kinetic energy is released given
the masses of 238.0508u, 144.9217u and 89.9306u for 238 U, 145 La
and 90Br, respectively, the neutron mass of 939.6 MeV/c² and
u =931.5 MeV/c2.
ii. A second decay path is through alpha decay:
238 U →
234Th + a.
92
90
By comparing formulas, show that the Coulomb barrier for the
fission process is over 8 times higher than that for the alpha pro-
cess.
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