uppose we find a 99% confidence interval for the true value of the population parameter, π, to be 0.75±0.04 . Which of the following conclusions is correct? We are 99% confident that the true value of the population proportion is between 67% and 83%. We are 99% confident that the true value of the population proportion is between 71% and 79%. We are 99% confident that the true value of the population proportion is 75%. The true value of the population proportion is between 71% and 79%. The true value of the population proportion is 75%.
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Suppose we find a 99% confidence interval for the true value of the population parameter, π, to be
0.75±0.04
.
Which of the following conclusions is correct?
- We are 99% confident that the true value of the population proportion is between 67% and 83%.
- We are 99% confident that the true value of the population proportion is between 71% and 79%.
- We are 99% confident that the true value of the population proportion is 75%.
- The true value of the population proportion is between 71% and 79%.
- The true value of the population proportion is 75%.
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- Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.You are trying to estimate the population mean p after taking a random sample from that population. Which of the following best represents a Margin of Error of about +/- 5% around the sample mean X? In other words, which best represents "95% confidence interval" around the observed mean, X? (In this notation, +/- stands for "plus or minus"; SD stands for "standard deviation"; and SE stands for "standard error.") p=X +- 2(SE) H= 2(SE) +/- X p =X+- 2(SD)If n=27, x¯(x-bar)=41, and s=3, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. _________< μ< _______
- If n=27, ¯x(x-bar)=36, and s=20, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place._____ < μ < _____One company recently conducted a survey in which 420 women and 420 men were asked "Are you satisfied with the work of the Minister of Health?". Of these, 155 men and 118 women said they were satisfied with the minister's work. Assume that the experimental design was correct. Questions 1 and 2 cover this survey. 1. Find the upper limit of 95% confidence interval for the difference in the proportion of men and women who are happy with the work of the Minister (let men be group 1). 1. 0.03. 2. 0.09. 3. 0.15. 4. It is not possible to apply a normal approach and therefore we can not calculate the confidence interval. 2. What is the rejection area if it is to be examined whether the proportion of men and women who are satisfied with the job of Prime Minister is different (use a = 0.05)? 1. RejectHO efz 1.96. 2. Reject HO if z> 1.64. 3. RejectHO efz> -1.96 or <1.96. 4. Insufficient information provided to answer this.Which interval is which? Alessandro constructed three confidence intervals, all from the same random sample. The confidence levels are 90%, 95%. and 99%. The confidence intervals are I. 4.5<µ<5.5 II. 4.3 <µ<5.7 III. 4.6<µ<5.4 Unfortunately, Alessandro has forgotten which confidence interval has which level. Match each confidence interval with its level. 4.5Which interval is which? Alessandro constructed three confidence intervals, all from the same random sample. The confidence levels are 90%, 95%, and 99%. The confidence intervals are I. 7.4<μ<8.6 II. 7.1Answer A through dBased on a random sample of 100 students at Community College in 95% confidence interval for U the mean age of all students at Community College is 21.2 years to 26.6 years ( 21.2<u<26.6). On the basis of this information decide whether you agree or disagree with each of the following statements explain how you decide. A. According to the confidence interval the mean age of all students at Community College cannot possibly be 23.1 years. B. The 99% confidence interval based on the sample taken above will give a smaller margin of error in the estimate of u. C. If the sample sizes decrease 240 the 95% confidence interval has a larger margin of error than the one obtained aboveIf a 95% confidence interval for two population proportions pi – p2 is a range of positive numbers, then what does this imply? With 95% confidence, the first population proportion is less than the second. With 95% confidence, there is no difference in the population proportions. O With 95% confidence, the first population proportion is greater than the second. O The relative size of the population proportions cannot be determined.If n=25, ¯x¯=47, and s=14, construct a confidence interval at a 95% confidence level. Give your answers to one decimal place. ____< μμ < ____Hunter is writing a report on the backgrounds of American presidents. He finds that the mean age of the 45 presidents is 55 years with the standard deviation of 6.59 years. Because Hunter took a statistics course, he calculates a 95% confidence interval for the mean age of all men who have been president to be 55 ± 1.98. Comment on this result. Question 8 options: Hunter can be 95% confident that the mean age of all presidents is 55 years. 95% of all the ages of the presidents lie between 55 ± 1.98. Hunter should have taken a larger sample to reduce the margin of error. Hunter is 95% confident that the mean age of all presidents lies between 53.02 and 56.98 years. The confidence interval makes no sense since Hunter has the entire population of ages.SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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