uppose the elements of an array A containing positive integers, denote the weights in kilograms. And we have a beam balance. We want to put the weights on both pans of the balance in such a way that for some index 0 < i < A.length - 1, all values starting from A[0], A[1], upto A[ i - 1], should be on the left pan. And all values starting from A[ i ] upto A[ A.length - 1] should be on the right pan and the left and right pan should be balanced. If such an i exists, return true. Else, return false. Input: [1, 1, 1, 2, 1] Output : true Explanation: (summation of [1, 1, 1] = summation of [2,1]) Input: [2, 1, 1, 2, 1] Output: false Input: [10, 3, 1, 2, 10] Output: true Explanation: (summation of [10, 3] = summation of [1,2,10]))

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Counting sort

The counting sort algorithm sorts an array’s contents by counting the repetition of each element that occurs in the array. A counting sort algorithm is a stable algorithm that works the best when the range of elements in the array is small, say for example from 0 to 9. The count which is the number of repetitions of an element in the array is mapped to an index of an auxiliary array, which is then saved in an auxiliary array. The counting sort algorithm has a stable time complexity of the order of O(size of array + size of auxiliary array). Let’s discuss the algorithm in detail as follows.