Given an array containing integers with N elements, and the sum of consecutive elements in the array with an integer k find out how many of them can be divided into a given integer k without remaining. The array contains n grain elements (array = [ array[0], array[1], …, array[n-1]]). K is a positive integer The sum of consecutive elements for any (first, next) pair first < next ise array[first] + array[next] Enter the Java code that returns the result for the integer array (array) and integer (k) entered in this scope Define the section to be calculated as a Java object (“Question2”). take the note sequence as an entry. public Question2(int[] input) In the “countSumPairs” method to be calculated, take the value “k” as an input and how many pieces in total return that the sum of the pairs is divided by the value “k” without remaining. public int countSumPairs(int k) example; public class Question2 { public Question2(int[] input) { } // Complete the countSumPairs function below public int countSumPairs(int k) { } } For example: let be an array (array) where we have positive integers as follows, Numbers = { 1, 3, 2, 6, 1, 2 } and if k = 3, the output will be given on the screen • (0, 2) à array[0] + array[2] = 1 + 2 = 3 • (0, 5) à array[0] + array[5] = 1 + 2 = 3 • (1, 3) à array[1] + array[3] = 3 + 6 = 9 • (2, 4) à array[2] + array[4] = 2 + 1 = 3 • (4, 5) à array[4] + array[5] = 1 + 2 = 3 a total of 5 pairs of elements were found for the value k = 3

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

Given an array containing integers with N elements, and the sum of consecutive elements in the array with an integer k find out how many of them can be divided into a given integer k without remaining.

The array contains n grain elements (array = [ array[0], array[1], …, array[n-1]]).

K is a positive integer

The sum of consecutive elements for any (first, next) pair

first < next ise array[first] + array[next]

Enter the Java code that returns the result for the integer array (array) and integer (k) entered in this scope

Define the section to be calculated as a Java object (“Question2”).

take the note sequence as an entry.

public Question2(int[] input)

In the “countSumPairs” method to be calculated, take the value “k” as an input and how many pieces in total return that the sum of the pairs is divided by the value “k” without remaining.

public int countSumPairs(int k)

example;

public class Question2 {
public Question2(int[] input) {
}
// Complete the countSumPairs function below
public int countSumPairs(int k) {
}
}

For example: let be an array (array) where we have positive integers as follows,
Numbers = { 1, 3, 2, 6, 1, 2 } and if k = 3, the output will be given on the screen
• (0, 2) à array[0] + array[2] = 1 + 2 = 3
• (0, 5) à array[0] + array[5] = 1 + 2 = 3
• (1, 3) à array[1] + array[3] = 3 + 6 = 9
• (2, 4) à array[2] + array[4] = 2 + 1 = 3
• (4, 5) à array[4] + array[5] = 1 + 2 = 3
a total of 5 pairs of elements were found for the value k = 3

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