Suppose 4-year-olds in a certain country average 3 hours a day unsupervised and that most of the unsupervised children live in ruralareas, considered safe. Suppose that the standard deviation is 1.8 hours and the amount of time spent alone is normally distributed.We randomly survey one 4-year-old living in a rural area. We are interested in the amount of time the child spends alone per day.O Part (a)O Part (b)O Part (c)Find the probability that the child spends less than 1 hour per day unsupervised.Write the probability statement.x< 1700What is the probability? (Round your answer to four decimal places.)0.3256Sketch the graph.X10-4-22468-4-224810X10X10-4-2246868O Part (d)What percent of the children spend over 10 hours per day unsupervised? (Round your answer to four decimal places.)0.1379X %O Part (e)90% of the children spend at least how long per day unsupervised? (Round your answer to two decimal places.)2346X hours

Given, Mean = 3 Standard deviation = 1.8

Answered: uppose 4-year- unsu day unsupervised…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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