Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,200 pounds and standard deviation 90 pounds. a. What is the probability that demand will exceed 1,000 pounds? b. What is the probability that demand will be between 1,100 and 1,300 pounds? c. The probability is 0.15 that demand will be more than how many pounds? Click the icon to view the standard normal table of the cumulative distribution function. a. The probability that demand will exceed 1,000 pounds is. (Round to four decimal places as needed:) ze ourt Eions tion Tc

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do a , b, c

Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,200 pounds and standard
deviation 90 pounds.
h
a. What is the probability that demand will exceed 1,000 pounds?
b. What is the probability that demand will be between 1,100 and 1,300 pounds?
c. The probability is 0.15 that demand will be more than how many pounds?
ntents
Click the icon to view the standard normal table of the cumulative distribution function.
lan
角
a. The probability that demand will exceed 1,000 pounds is
(Round to four decimal places as needed:)
& Resourcel
ssible Resourt
hase Options
mmunication Tc
Transcribed Image Text:Anticipated consumer demand in a restaurant for free range steaks next month can be modeled by a normal random variable with mean 1,200 pounds and standard deviation 90 pounds. h a. What is the probability that demand will exceed 1,000 pounds? b. What is the probability that demand will be between 1,100 and 1,300 pounds? c. The probability is 0.15 that demand will be more than how many pounds? ntents Click the icon to view the standard normal table of the cumulative distribution function. lan 角 a. The probability that demand will exceed 1,000 pounds is (Round to four decimal places as needed:) & Resourcel ssible Resourt hase Options mmunication Tc
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