upplemental Problems from Chapter 2 CCC-Dr. Feudale A 1.446 g sample of potassium reacts with 8.178 g of chlorine to produce potassium chloride as the only product. After the reaction, 6.867 g of chlorine remains unreacted. What mass of potassium chloride was formed? 5.656 Mass
upplemental Problems from Chapter 2 CCC-Dr. Feudale A 1.446 g sample of potassium reacts with 8.178 g of chlorine to produce potassium chloride as the only product. After the reaction, 6.867 g of chlorine remains unreacted. What mass of potassium chloride was formed? 5.656 Mass
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I just asked this question and do not understand the answer. Where did 70.906 come from? What are we doing to get the answer? I'm completely lost. It's number 1 on the worksheet
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Answered: How to solve number 1...
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Step 1
mass of chlorine reacted during the reaction=
8.178-6.867
= 1.311g
Atomic Mass of KCl = 74.5513g/mol
Atomic Mass of Cl = 34.45g
Step 2
→ 2kl
At. massof d= 35.453
2K + a
9069g chbrne gives
a Q mole idax74.S5I3g gf kcl
1 mde 1.e. 70
2x74.5513
70.906
chloxine
gives
= 97.73675x2
70.906
= R. 75679g 9 ka ie.
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Transcribed Image Text:9:41
Answered: How to solve number 1...
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A Q&A I 8
Science / Chemistry / Q&A Library / How to solve number 1 s...
How to solve number 1 step by step
Step 1
mass of chlorine reacted during the reaction=
8.178-6.867
= 1.311g
Atomic Mass of KCl = 74.5513g/mol
Atomic Mass of Cl = 34.45g
Step 2
→ 2kl
At. massof d= 35.453
2K + a
9069g chbrne gives
a Q mole idax74.S5I3g gf kcl
1 mde 1.e. 70
2x74.5513
70.906
chloxine
gives
= 97.73675x2
70.906
= R. 75679g 9 ka ie.
FREE QUESTIONS X
was tnis solution helpful?
Privacy - Terms
II

Transcribed Image Text:'chloride as the only product. After the reaction, 6.867 g of chlorine remains unreacted.
Chemistry I Science
Supplemental Problems from Chapter 2
1. A1.446 g sample of potassium reacts with 8.178 g of chlorine to produce potassium
CCC – Dr. Feudale
chloride as the only product. After the reaction, 6.867 g of chlorine remains unreacted.
What mass of potassium chloride was formed?
.178
5.65
Mass of KCl produced = 2.757 g
0.1768
2.
. 1 liter of nitrogen gas reacts with 3 liters of hydrogen gas to form 2 liters of an unknown
gas. Determine the formula of the gas.
N2 + 3H2
→ 2NH3
3. Fill in the missing information for the following neutral elements. Be sure to provide the
mass number along with the chemical symbol in the first column.
Number of
Electrons
Number of
Mass Number
Number of
Chemical
Neutrons
Protons
24
52
Symbol
28
24
47
107
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