university claims that their employment rate directly after graduation is 70%. In a sample of 300 graduates, 231 found to have gained employment directly after graduation. Test the claim that the university's employment rate after graduation is larger than 70% at the 0.005 significance level. The null and alternative hypothesis would be:   H0:p≤0.7H0:p≤0.7 H1:p>0.7H1:p>0.7 H0:μ≥0.7H0:μ≥0.7 H1:μ<0.7H1:μ<0.7 H0:μ≤0.7H0:μ≤0.7 H1:μ>0.7H1:μ>0.7 H0:p≥0.7H0:p≥0.7 H1:p<0.7H1:p<0.7 H0:p=0.7H0:p=0.7 H1:p≠0.7H1:p≠0.7 H0:μ=0.7H0:μ=0.7 H1:μ≠0.7H1:μ≠0.7 The test is:   right-tailed two-tailed left-tailed The test statistic is:  (to 2 decimals) The p-value is:  (to 4 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

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Q: ??

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A:

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A: It is given that P-value = 0.035 Level of significance = 5% = 0.05

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A: Given,nM=80  ,  pM^=0.35nF=80  ,   pF^=0.50α=0.01

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Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.