factors that allow you to convert between theamount of solute and its corresponding amount ofsolution Examples of units of concentration areshown below for an equivalent ratio of potassiumiodide (KI) amount over solution amountConventionalConcentration expression ofConvertsbetweenthe ratio0.3 M KI0.3 mol KIL solutionmoles of soluteand volume ofsolutioncontaining thatamount ofsolutemass of solute5g Kl5% KIand the mass ofsolution100 g solution containing thatmass of soluteUnits of Concentration: Molarity and Mass Percentfactors that allow you to convert between theamount of solute and its corresponding amount ofsolution. Examples of units of concentration areshown below for an equivalent ratio of potassiumlodide (KI) amount over solution amountConventionalConcentration expression cthe ratioConvertsbetween0.3 M KI0.3 ml KlL solutionmoles of soluteand volume ofsolutioncontaining thatamount ofsolutemass of soluteand the mass ofsolution5% KI5g Kl100 g solutioncontaining thatmass of soluteReview Constacts Periodic TablePart APotassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animalthat ingests it. The median lethal dose of KCN for a person weighing 175 lb (79.4 kg) is 9.75×10 mol.What volume of a 0.0550 M KCN solution contains 9.75x10 mol of KCN?Express the volume to three significant figures and include the appropriate units.View Available Hint(s)μÅ?Volume ValueUnits15 of 23 >Review Constants I Periodic TablePart BGastric acid pH can range from 1 to 4, and most of the acid is HCLFor a sample of stomach acid that is 9.80x10 Min HCI, how many moles of HCI are in 15.8 ml of the stomachacid?Express the amount to three significant figures and include the appropriate units.View Available Hint(s)HÅamount of HCI-UnitsValue

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units of concentration are quivalent ratio of potassium wer solution amount ventional ression of Converts between the ratio moles of solute and volume of solution 3 mol KI solution containing that amount of solute mass of solute 5g Kl and the mass of solution containing that mass of solute Part A Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it. The median lethal dose of KCN for a person weighing 175 lb (79.4 kg) is 9.75x10 mol What volume of a 0.0550 M KCN solution contains 9.75x10 mol of KCN? Express the volume to three significant figures and include the appropriate units. View Available Hint(s) μÅ Volume Value Units

units of concentration are quivalent ratio of potassium wer solution amount ventional ression of Converts between the ratio moles of solute and volume of solution 3 mol KI solution containing that amount of solute mass of solute 5g Kl and the mass of solution containing that mass of solute Part A Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it. The median lethal dose of KCN for a person weighing 175 lb (79.4 kg) is 9.75x10 mol What volume of a 0.0550 M KCN solution contains 9.75x10 mol of KCN? Express the volume to three significant figures and include the appropriate units. View Available Hint(s) μÅ Volume Value Units

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the mass of propanol present in a 3.50 molal aqueous solution of propanol, C3H7OH? The molar mass of propanol is 60.094 g/mol. Mass Solute = [?] g C3H₂OH Mass Solute (g) Copyright © 2003-2022 International Academy of Science. All Rights Reserved. DELL Enter Just Short Answer q Jefferson, Thomas
A bubble of air escaping from a diver's mask rises from a depth of 108 ft to the surface where the pressure is 1.00 atm. Initially, the bubble has a volume of 10.0 mL. Assuming none of the air dissolves in the water, how many times larger is the bubble just as it reaches the surface? Use this data: 1. The density of seawater is approximately 1.025 g ml-1 2. The density of mercury is 13.6 g ml-1 i times larger Use your answer to explain why scuba divers constantly exhale as they slowly rise from a deep dive. Since the pressure by a factor of approximately i , the volume must by a factor of approximately i Divers exhale to the amount of gas in their lungs, so it does not to a volume than the diver's lungs.
What is the molarity of a solution prepared using the given amount of solute and total volume of solution? a. 7.8 mol of KCI in 3.30 L of solution: M b. 0.17 mol of NaNOz in 279 mL of solution: M < Prev 10 of 16
Atomic weights( g/mol): H=1 K=39 O=12 P= 31 C= 12 Na = 23 CI = 35.45 1. Find the Normality of NaOH and Normality of HCI from the following data: Weight of KHP Final Reading NaOH Initial Reading Final reading HCI Initial Reading HCI 2.053 g 39.47 mL 0.02 ml 0.32 mL 0.01 mL Iml HCI 0.9690 ml NAOH
6. For each compound, Determine the equivalent moles of H+ accepted or donated, then calculate the normality of the solution for the given molarity. Refer to equation 5. Equivalents Molarity Normality HCI 1.86 M HCI H;SO. 0.93 M H,SO. H,PO 0.62 M HPO. NaOH 1.024 M NAOH КОН 0.086 M KOH Na:CO Ba(OH): 0.512 M Na:CO 0.043 M Ba(OH):
Oxygen is soluble in water, much to the benefit of aquatic life forms. At 25 °C, the solubility of oxygen is about 7×10–6 g/cm3, and the pressure of O2 is about 20% of the atmospheric pressure. Could the oxygen dissolved in water affect your experimental results significantly?
At 20 °C, an aqueous solution of NaCl was prepared by dissolving 11.44 g NaCl (Molar Mass = 58.44) in 45.76 g H20 (Molar Mass 18.02). The density of the NaCl solution (at 20 °C) is 1.1478 g/mL. Which of the following statements is consistent with the data given? %3D The volume of the solution is 57.20 mL. The solution contains 25.00% NaCl by mass. C The molality of the solution is 3.423 molal. The molarity of the solution is 3.929 M NaCl.
Use the solubility curve below to answer the following questions: 150 140 130 120 110 100 NANO3 90 80 70 60 NH&Cl KCI NaCi 50 40 30 20 KCIO3 10 Ce2(SOals O 10 20 30 40 50 60 70 80 90 100 Temperature (c) Q1) As the temperature increases, the solubility of the NH3 in water Q2) The solute, NH3, is MOST likely a (increases/decreases/stays the same). (solid, liquid, or gas). Q3) How many grams of NH4CI are dissolved in 500 g of water at 90 °C? Q4) If you had 50 grams of NH4CI in 100 g of water at 40 °C, would the solution be saturated, unsaturated, or supersaturated? Q5) You heat a solution of KCIO3 to 80°C and saturate the solution. You then allow the solution to cool down to 50°C. How many grams of solute would precipitate out of the solution? NH3 per 100 g H,0 Grams of solute ONO CON
1/T (K-¹) 2 N₂O5(g) → 4NO2(g) + O₂(g) K(S-¹) 4.87 x 10-3 1.50 x 10-³ 4.98 x 10-4 1.35 x 10-4 3.46 x 10-5 7.87 x 10-7 T (K) 338 0.0030 328 0.0030 318 0.0031 308 0.0032 298 0.0034 273 6.0037 The data in the table above provide the temperature dependence of the rate constant for the reaction shown. Complete the table with required information to 2 significant figures each. - a=-12571.42 In K, no units 5.3 - 6.5 7.6 8.9 Carefully construct a neat and well labelled graph/plot of In K (y-axis) versus 1/T (x-axis) in the appropriate quadrant (s), using EXCEL or the template below; then determine the slope and activation energy, Ea for the given reaction. Recall that the Arrhenius Equation is represented in a more useful form as In K= In A- (Ea/RT) & R= 8.31 x 10-³ kJ/mol-K. Determine by calculation, the value of Ea in kj/mole given that, slope = -E/R slope: - Ca = slope & - Ga= €ag Ea=-(-12571.42) x (8.3) x 10 Rg/mol-K) Ea=104.47 kj/md 10.3 - 14.1 Y = (-14.1)-(-5.3) = -8.8 x = (0.0037) -…
Concentration is the amount of solute dissolved in a certain amount of solution: amount of solute concentration of a solution amount of solution Solution concentrations are usually given as one of the following: Mass percent (m/m)–the mass of the solute in grams for exactly 100 g of solution Volume percent (v/v)–the volume of solute in exactly 100 mL of solution Mass/volume percent (m/v)–the mass of solute in grams for exactly 100 mL of solution Molarity (M) – the number of moles of solute in exactly 1 L of solution Part A Calculate the mass percent (m/m) of a solution prepared by dissolving 56.79 of NaCl in 155.2 g of H2O. Express your answer to four significant figures. • View Available Hint(s) ? Mass percent (m/m) = % %3D
A solution is made by dissolving 17.8 g of magnesium sulfite, MgSO3, in enough water to make exactly 100 mL of solution. Calculate the concentration (molarity) of MgSO3 in mol/L (M). 1.71 mole MgSO3/L 2.71 mole MgSO3/L 3.17 mole MgSO3/L 2.17 mole MgSO3/L