UNITS; DO NOT WRITE LETTERS). During a lecture demonstration of single-slit diffraction, a laser beam that has a wavelength À = 600 [nm] passes through a vertical slit of gap a = 0.25 [mm] and hits a screen. All angles are in degrees. A diffraction pattern is observed on the screen, as shown in the below figure. O sin (1x600x10 o [m] L a) [:. Considering λ = 600 [nm] and a = 0.25 [mm], the angle corresponding to the first dark fringe (8₂) will be given by: Screen W= y [m] W 0.25x10) sin((1/2)x600x10 0.25x10-3 b) [ Considering = 600 [nm] and a = 0.25 [mm], calculate the angle corresponding to the first dark fringe (0₁) 0₁ = If the angle corresponding to the first dark fringe is found to be 8₁ = 0.24*, and the screen is located at a distance L = 7 [m] from the slit. Calculate y₁, the location of the first dark fringe. y₁ = -) sin((1/2)x0.25x10-³ 600x10 d) i If the location of the first dark fringe is found to be y₁ = 0.13 [m]. Find w, the width of the central bright fringe.
UNITS; DO NOT WRITE LETTERS). During a lecture demonstration of single-slit diffraction, a laser beam that has a wavelength À = 600 [nm] passes through a vertical slit of gap a = 0.25 [mm] and hits a screen. All angles are in degrees. A diffraction pattern is observed on the screen, as shown in the below figure. O sin (1x600x10 o [m] L a) [:. Considering λ = 600 [nm] and a = 0.25 [mm], the angle corresponding to the first dark fringe (8₂) will be given by: Screen W= y [m] W 0.25x10) sin((1/2)x600x10 0.25x10-3 b) [ Considering = 600 [nm] and a = 0.25 [mm], calculate the angle corresponding to the first dark fringe (0₁) 0₁ = If the angle corresponding to the first dark fringe is found to be 8₁ = 0.24*, and the screen is located at a distance L = 7 [m] from the slit. Calculate y₁, the location of the first dark fringe. y₁ = -) sin((1/2)x0.25x10-³ 600x10 d) i If the location of the first dark fringe is found to be y₁ = 0.13 [m]. Find w, the width of the central bright fringe.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Problem 4
For the parts of the below question, fill in the
empty boxes with your answer (YOUR ANSWER
MUST BE ONLY A NUMBER; DO NOT WRITE
UNITS; DO NOT WRITE LETTERS).
During a lecture demonstration of single-slit
diffraction, a laser beam that has a wavelength >
= 600 [nm] passes through a vertical slit of gap a =
0.25 [mm] and hits a screen. All angles are in
degrees.
A diffraction pattern is observed on the screen, as
shown in the below figure.
→T
sin (1x600x10
0.25x10-³
L
a) [:.
Considering λ = 600 [nm] and a = 0.25
[mm], the angle corresponding to the first dark
fringe (8₁) will be given by:
[m]
Screen
y
w =
[m]
W
0.25x10-3
600x10
) sin((1/2)x0.25x10-³
Considering = 600 [nm] and a = 0.25
b) [
[mm], calculate the angle corresponding to the
first dark fringe (0,₁)
0₁ =
-) sin((1/2)x600x10-
c) {
If the angle corresponding to the first
dark fringe is found to be 0₁ = 0.24°, and the
screen is located at a distance L = 7 [m] from the
slit. Calculate y₁, the location of the first dark
fringe.
y₁ =
d) i
If the location of the first dark fringe is
found to be y₁ = 0.13 [m]. Find w, the width of the
central bright fringe.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3e4bde1-0428-456d-8670-71dcd956721b%2F5adecbf1-58b0-4223-94bb-082b42de8340%2Fcerdax9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 4
For the parts of the below question, fill in the
empty boxes with your answer (YOUR ANSWER
MUST BE ONLY A NUMBER; DO NOT WRITE
UNITS; DO NOT WRITE LETTERS).
During a lecture demonstration of single-slit
diffraction, a laser beam that has a wavelength >
= 600 [nm] passes through a vertical slit of gap a =
0.25 [mm] and hits a screen. All angles are in
degrees.
A diffraction pattern is observed on the screen, as
shown in the below figure.
→T
sin (1x600x10
0.25x10-³
L
a) [:.
Considering λ = 600 [nm] and a = 0.25
[mm], the angle corresponding to the first dark
fringe (8₁) will be given by:
[m]
Screen
y
w =
[m]
W
0.25x10-3
600x10
) sin((1/2)x0.25x10-³
Considering = 600 [nm] and a = 0.25
b) [
[mm], calculate the angle corresponding to the
first dark fringe (0,₁)
0₁ =
-) sin((1/2)x600x10-
c) {
If the angle corresponding to the first
dark fringe is found to be 0₁ = 0.24°, and the
screen is located at a distance L = 7 [m] from the
slit. Calculate y₁, the location of the first dark
fringe.
y₁ =
d) i
If the location of the first dark fringe is
found to be y₁ = 0.13 [m]. Find w, the width of the
central bright fringe.
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