uniform track until coming to rest at point B. 98. In the diagram below, a toy car having a mass of 4.00 X 10 2 kilogram starts from rest at point A and travels 3.60 meters along a A m = 4.00 x 10-2 kg B 0.80 m 0.50 m
uniform track until coming to rest at point B. 98. In the diagram below, a toy car having a mass of 4.00 X 10 2 kilogram starts from rest at point A and travels 3.60 meters along a A m = 4.00 x 10-2 kg B 0.80 m 0.50 m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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please help with questions 94,95,96,97,98 and 99 altogether because they are for one whole problem
![lowest point of its swing when released from
a vertical
of h
creased
97. Compared to the sphere's speed through the
h, the sphere's speed through the lowest point
when released from 2h would be
(2) greater
(3) the same
98. In the diagram below, a toy car having a mass
of 4.00 X 10 2 kilogram starts from rest at
point A and travels 3.60 meters along a
uniform track until coming to rest at point B.
(1) lower
sent the
of the
A to
A
m = 4.00 x 10-2 kg
0.80 m
0.50 m
Calculate the magnitude of the frictional force
acting on the car. [Assume the frictional force is
constant.]
99. A car has a mass of 1.00 X 10 kilograms.
Calculate the work done in moving the car at
constant speed a distance of 250 meters along
a horizontal asphalt-paved road.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc69cdd85-cca7-4d84-b022-8594381da460%2F21d38a87-030c-42c6-a86b-34472dcc50de%2Fjgsdkm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:lowest point of its swing when released from
a vertical
of h
creased
97. Compared to the sphere's speed through the
h, the sphere's speed through the lowest point
when released from 2h would be
(2) greater
(3) the same
98. In the diagram below, a toy car having a mass
of 4.00 X 10 2 kilogram starts from rest at
point A and travels 3.60 meters along a
uniform track until coming to rest at point B.
(1) lower
sent the
of the
A to
A
m = 4.00 x 10-2 kg
0.80 m
0.50 m
Calculate the magnitude of the frictional force
acting on the car. [Assume the frictional force is
constant.]
99. A car has a mass of 1.00 X 10 kilograms.
Calculate the work done in moving the car at
constant speed a distance of 250 meters along
a horizontal asphalt-paved road.
![Base your answers to questions 94 through 97 on
the information and diagram below.
A 1.00-kilogram sphere M, suspended by a string
from point P, is lifted to a height h. The sphere is
released and passes through the lowest point in
its swing at a speed of 10.0 meters per second.
[Neglect friction.]
M.
10.0 m
1.00 kg
94. Calculate the height from which the sphere was
released.
95. Calculate the magnitude of the centripetal force
on the sphere as it passes through the lowest
point in its swing.
96. The magnitude of the centripetal force on the
sphere could be halved as it passes through the
lowest point in its swing by doubling the
(1) weight of the sphere, only
(2) length of the string, only
(3) height h and the weight of the sphere
(4) the length of the string and height h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc69cdd85-cca7-4d84-b022-8594381da460%2F21d38a87-030c-42c6-a86b-34472dcc50de%2Fn7g837l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Base your answers to questions 94 through 97 on
the information and diagram below.
A 1.00-kilogram sphere M, suspended by a string
from point P, is lifted to a height h. The sphere is
released and passes through the lowest point in
its swing at a speed of 10.0 meters per second.
[Neglect friction.]
M.
10.0 m
1.00 kg
94. Calculate the height from which the sphere was
released.
95. Calculate the magnitude of the centripetal force
on the sphere as it passes through the lowest
point in its swing.
96. The magnitude of the centripetal force on the
sphere could be halved as it passes through the
lowest point in its swing by doubling the
(1) weight of the sphere, only
(2) length of the string, only
(3) height h and the weight of the sphere
(4) the length of the string and height h
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