Under the current market conditions Bond 1 has a price of 90 and a Mccauley duration of 10, and Bond 2 has a price of 110 and Macauley duration of 15. A portfolio is created with a combination of face amount F₁ of Bond 1 and F2 of Bond 2. The combined face amount of the portfolio is F1+F2= 100, and the Macauley duration of the portfolio is 12.5. Set up the equations for finding the portfolio value X. (a) 15X=9F₁ + 16.5(100-F₁), X= .9F₁+1.1(100-F₁) (b) 12.5X = 9F₁ +15(100-F₁), X = .9F₁+1.1(100-F₁) (c) 12.5X = 9F₁ + 16.5(100-F₁), X = .9F₁+1.1(100-F₁) (d) 12.5X = 10Fi + 16.5(100-F1), X = .9F₁ + 1.1(100-F₁) (e) none of these
Under the current market conditions Bond 1 has a price of 90 and a Mccauley duration of 10, and Bond 2 has a price of 110 and Macauley duration of 15. A portfolio is created with a combination of face amount F₁ of Bond 1 and F2 of Bond 2. The combined face amount of the portfolio is F1+F2= 100, and the Macauley duration of the portfolio is 12.5. Set up the equations for finding the portfolio value X. (a) 15X=9F₁ + 16.5(100-F₁), X= .9F₁+1.1(100-F₁) (b) 12.5X = 9F₁ +15(100-F₁), X = .9F₁+1.1(100-F₁) (c) 12.5X = 9F₁ + 16.5(100-F₁), X = .9F₁+1.1(100-F₁) (d) 12.5X = 10Fi + 16.5(100-F1), X = .9F₁ + 1.1(100-F₁) (e) none of these
Essentials Of Investments
11th Edition
ISBN:9781260013924
Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Chapter1: Investments: Background And Issues
Section: Chapter Questions
Problem 1PS
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Transcribed Image Text:Under the current market conditions Bond 1 has a price of 90 and a Mccauley duration of 10, and Bond 2
has a price of 110 and Macauley duration of 15. A portfolio is created with a combination of face amount
F₁ of Bond 1 and F2 of Bond 2. The combined face amount of the portfolio is F1+F2= 100, and the
Macauley duration of the portfolio is 12.5. Set up the equations for finding the portfolio value X.
(a) 15X9F1 + 16.5(100-F₁), X=9F₁+1.1(100-F₁)
(b) 12.5X9F1 +15(100-F₁), X= .9F₁ + 1.1(100-F₁)
(c) 12.5X = 9F₁ + 16.5(100-F₁), X= .9F₁+1.1(100-F₁)
(d) 12.5X = 10F₁ +16.5(100-F₁), X = .9F₁+1.1(100-F₁) (e) none of these
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