Under the action of force P, the constant acceleration of block B is 5.7 ft/sec² up the incline. For the instant when the velocity of B is 3.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A= OB/A = VC= 18 i i i ft/sec ft/sec² ft/sec

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Under the action of force P, the constant acceleration of block B is 5.7 ft/sec² up the incline. For the instant when the velocity of B is 3.6
ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to
A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable.
Answers:
VB/A
OB/A =
VC=
18
i
i
ft/sec
ft/sec²
ft/sec
Transcribed Image Text:Under the action of force P, the constant acceleration of block B is 5.7 ft/sec² up the incline. For the instant when the velocity of B is 3.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A OB/A = VC= 18 i i ft/sec ft/sec² ft/sec
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