I need to know if my D vector is right, or is it suppose to be 0i+11j+0k, need clarification
I need to know if my D vector is right, or is it suppose to be 0i+11j+0k, need clarification
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Question
I need to know if my D vector is right, or is it suppose to be 0i+11j+0k, need clarification
![Determine the magnitude of the projected
component of the 200 lb force acting along the axis
BC of the pipe. (Note: this is basically problem #2-
117 with a few numbers changed). F= 2001b
-31+03 тов
BOT+O+OF
2 = 61+49-3K
B = 0+12₁ +0²
4 ft
+ BCy + BC₂ =
7.81
30 IBU IBC |BC| -782-
6821+.51223-.38412
BC
3 ft
7.81
C
6 ft
51225
6-2 = (0-6)^- (12-4)Ĵ-(0-3)
61 +8₁ +31 |CD| = √-6²+82 +3² = √109=10.44
ED_CDx+ CDY + CD z
CDI ICDI ICPI
57471+.76633+.2874 k
•UCD² 200 (-57471+.76633+.2874 12) = -114.941+ 153.265+57.4812²2
- B=(6-0) ₁, (4-0)5₁ (-3-0) € = (0^+43-3 € 18c/= √x² + y² + 2²
60² +42 +-32= √√61 = 7.81 = |BC| BC=61 +4J-31]
BC-BCX
1 +
1
F-200 lb CD
(CD ² = [(10 414 7] + [ 10 4 4 3] + [ 10.34 4 1/2]
10,44
57477
76635
2874k
ICDI= √√x² + y² +2² magnitude of CD
8 ft
.38111
(-114.941 +153.263+57.482).(-76829+.51223-38412)-/F
-88.30+78.50-22.08-1-31.881 = 31.88 lbs](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae2b6eb5-0b25-4f0e-97e4-54bb25b6155d%2F015f1998-0130-4c45-8cd0-0ab7024c9bfa%2Fqcg07to_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the magnitude of the projected
component of the 200 lb force acting along the axis
BC of the pipe. (Note: this is basically problem #2-
117 with a few numbers changed). F= 2001b
-31+03 тов
BOT+O+OF
2 = 61+49-3K
B = 0+12₁ +0²
4 ft
+ BCy + BC₂ =
7.81
30 IBU IBC |BC| -782-
6821+.51223-.38412
BC
3 ft
7.81
C
6 ft
51225
6-2 = (0-6)^- (12-4)Ĵ-(0-3)
61 +8₁ +31 |CD| = √-6²+82 +3² = √109=10.44
ED_CDx+ CDY + CD z
CDI ICDI ICPI
57471+.76633+.2874 k
•UCD² 200 (-57471+.76633+.2874 12) = -114.941+ 153.265+57.4812²2
- B=(6-0) ₁, (4-0)5₁ (-3-0) € = (0^+43-3 € 18c/= √x² + y² + 2²
60² +42 +-32= √√61 = 7.81 = |BC| BC=61 +4J-31]
BC-BCX
1 +
1
F-200 lb CD
(CD ² = [(10 414 7] + [ 10 4 4 3] + [ 10.34 4 1/2]
10,44
57477
76635
2874k
ICDI= √√x² + y² +2² magnitude of CD
8 ft
.38111
(-114.941 +153.263+57.482).(-76829+.51223-38412)-/F
-88.30+78.50-22.08-1-31.881 = 31.88 lbs
Expert Solution
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Given,
Position vectors and location of points
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