The x component of vector A is -14.5 m and they component is +45.6 m. (a) What is the magnitude of A? (b) What is the angle between the direction of A and the positive direction of x?

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The x component of vector A is -14.5 m and they component is +45.6 m. (a) What is the magnitude of A? (b) What is the angle
between the direction of A and the positive direction of x?
(a) Number i
(b) Number i
Units
Units
m
° (degrees)
Transcribed Image Text:→ The x component of vector A is -14.5 m and they component is +45.6 m. (a) What is the magnitude of A? (b) What is the angle between the direction of A and the positive direction of x? (a) Number i (b) Number i Units Units m ° (degrees)
Expert Solution
Step 1

Given,AX = -14.5 m i^AY = + 45.6 m j^A=AX+AY A=AX2+AY2A=(14.5)2+(45.6)2A=47.85 m

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