Under dissolving indium chloride (InCℓ) in hydrochloric acid (HCℓ), In+ (aq) undergoes disproportionation reaction according to the following unbalanced equation. In+ (aq) = In (s) + In3+ (aq) This disproportionation follows a first – order kinetics with a half-life of 667 s. (a) What is the concentration of In+(aq) after 1.25 hours if the initial solution of In+ (aq) was prepared by dissolving 2.38 g InCℓ (s) in 5.00 x 102 mL of dilute hydrochloric acid? (b) What mass of In (s) is formed after 1.25 hours? (c) Determine the rate constant k, for this reaction.

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Under dissolving indium chloride (InCℓ) in hydrochloric acid (HCℓ), In+ (aq) undergoes disproportionation reaction according to the following unbalanced equation.


In+ (aq) = In (s) + In3+ (aq)

This disproportionation follows a first – order kinetics with a half-life of 667 s.
(a) What is the concentration of In+(aq) after 1.25 hours if the initial solution of In+ (aq) was prepared by dissolving 2.38 g InCℓ (s) in 5.00 x 102 mL of dilute hydrochloric acid?
(b) What mass of In (s) is formed after 1.25 hours?

(c) Determine the rate constant k, for this reaction.

(d) Sketch a graph of [In+] versus time (sec) over a period of 3 hours.

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