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The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x

The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Jave niISWCI The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: 2+ Fe(phen) 3 2* +3 H 30 * + 3 H 20 → Fe(H 20) 6 + 3 phenH If the activation energy, E a, is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1, what is the rate constant at 45°C? 9.6 x 10° min-1 1.1 x 10 min 1 9.3 x 10 min 1 1.1 x 10 min 1
Transcribed Image Text:Jave niISWCI The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: 2+ Fe(phen) 3 2* +3 H 30 * + 3 H 20 → Fe(H 20) 6 + 3 phenH If the activation energy, E a, is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1, what is the rate constant at 45°C? 9.6 x 10° min-1 1.1 x 10 min 1 9.3 x 10 min 1 1.1 x 10 min 1
Expert Solution
Step 1

Given :-

Activation Energy = 126KJ/mol

Rate constant at 30℃ = 9.8×10-3 min-1

To find :-

Rate constant at 45℃ = ?

 

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