U — х a b. с d
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A: The vector force acting on system kept in a potential field U is given by- F→=-∂U∂xi^-∂U∂yj^
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A: To determine: (a) The work done by the force on the particle (b) The angle between F→ and ∆r→…
Q: The figure below shows three forces applied to a trunk that moves leftward by 1.3 over a…
A:
Q: With reference to the diagram above, select the correct expression for the work done by friction (W…
A: W = F.S Cosθ Here, F =Force = Friction = UN = Uk *Mg cos 15° S = net displacement parallel or…
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A: The objective of the question is to find the work done by the force on the particle and the angle…
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A: (a) The force acting on the object can be given as, Fx=dUxdx=ddx3x4-2x2=12x3-4x…
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Q: The figure shows three forces applied to a trunk that moves leftward by 3.01 mover a frictionless…
A: F1 = 4. 5N F2= 9.48N F3 = 2.85N angle is 60° We have to find the net work done
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A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…
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A: Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…
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Q: A potential energy function for a system in which a two-dimensional force acts is of the form U =…
A: The expression for the force is,
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A: (d). the work done by the gravitational force is zero. Because the gravitational force on the box…
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Q: With reference to the diagram above, select the correct expression for the work done by gravity (Wg)…
A: Work = F. S .Cosθ Here, f= force = mg s = net displacement parallel or antiparallel to force = h θ…
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Q: 5. A mass m moves in one dimension along the positive â axis (x > 0) under the influence of a force…
A: MECHANICS
A marble moves along the
x-axis. The potential-energy function
is shown in Fig. . (a) At
which of the labeled x-coordinates
is the force on the marble zero?
(b) Which of the labeled x-coordinates
is a position of stable equilibrium?
(c) Which of the labeled x-coordinates
is a position of unstable
equilibrium?


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- A block of mass m is on an inclined ramp. The ramp makes anangle θ with respect to the horizontal, as shown. The ramp hasfriction, with coefficient of kinetic friction μk and static friction μs.This experiment takes place on earth.The block has an initial speed of v up the ramp. It travels adistance d along the ramp before it stops.Answer using variables, please d) Calculate the work done by the Friction force as the block travels the distance d.Is it positive, negative, or zero?e) If the block comes to rest, how far has it travelled?Use the work-energy principle and your results of parts b), c), and d).f) Briefly (one sentence) explain why this problem could not be solved using conservation ofenergy.U(x)=9.0x^2-8.0x^3 Determine the force Fx associated with this potential-energy function Assuming no other forces act on the object, at what positions is this object in equilibrium? Which of these equilibrium positions are stable and which are unstable? (Hint: use the 2ndderivative)An external force acts on a particle during a trip from one point to another and back to that same point. This particle is only effected by conservative forces. Does this particle's kinetic energy and potential change as a result of this trip?
- A 68.3-kg skier coasts up a snow-covered hill that makes an angle of 25.5 ° with the horizontal. The initial speed of the skier is 9.77 m/s. After coasting a distance of 1.45 m up the slope, the speed of the skier is 3.60 m/s. (a) Find the work done by the kinetic frictional force that acts on the skis. (b) What is the magnitude of the kinetic frictional force? (a) Number i (b) Number i Units Units 0The potential energy of a system is given by: U(x,y,z)=5(J/m^2) x^2 + 7(J/m^3) xy^2 + 8(J/m^2) zy Find: The force acting on the system. Write the forces as the sum of its components. The magnitude of the force when x=1, y=0, z=2A person of weight 500 N skis 500 m down a frictionless slope covered by snow that makes an angle 30◦ to the horizontal. The person is at rest initially. There are two forces acting on the person – the weight and the normal reaction force. (a) How much work is done by the person’s weight and the normal reaction force. Find the velocity of the person at the 500 m mark down the slope using the Work-Energy Theorem and the velocity of the person at the 500 m mark using the conservation of mechanical energy. (b) If there is a friction of 50 N, find the velocity of the person at the 500 m mark. What is the work done by the person’s weight? What is the work done by friction?
- Can someone help with second question? ThanksA block with mass m = 1.14 kg is placed against a spring on a frictionless incline with angle = 22.0° (see the figure). (The block is not attached to the spring.) The spring, with spring constant k = 15 N/cm, is compressed 24.1 cm and then released. (a) What is the elastic potential energy of the compressed spring? (b) What is the change in the gravitational potential energy of the block-Earth system as the block moves from the release point to its highest point on the incline? (c) How far along the incline is the highest point from the release point?