U-factor measures how well a product prevents heat from escaping a home or building (thermal conductivity). U-factor ratings generally fall between 0.15 and 1.20. (See more at: http://www.nfrc.org/windowratings/Energy- ratings.html#sthash.EUkrrint dpuf) A lower U-factor means a better-insulating window. The more common term R-value refers to the resistance of the window to heat conduction, and it is the inverse of the U- factor (that is, R-value = 1/U-factor). Better windows have high R-values and low U-factors. Determine all surface type of areas in Table 8-1 from the house in figure 1 and calculate R-values with the given U-factor Table 8 -1 Surface Type Size of area U-factor R-values (width x height = ff') a) Walls 0.06 b) Ceiling (**Assume the ceiling area is the same as rectangular floor area, A=L x W) 0.025 c) Total window x 8 ea (argon-filled, double glazed for all windows) 0.35 d) Total door (insulated steel entry doors) x 2ea 0.20

U-factor measures how well a product prevents heat from escaping a home or building (thermal conductivity). U-factor ratings generally fall between 0.15 and 1.20. (See more at: http://www.nfrc.org/windowratings/Energy- ratings.html#sthash.EUkrrint dpuf) A lower U-factor means a better-insulating window. The more common term R-value refers to the resistance of the window to heat conduction, and it is the inverse of the U- factor (that is, R-value = 1/U-factor). Better windows have high R-values and low U-factors. Determine all surface type of areas in Table 8-1 from the house in figure 1 and calculate R-values with the given U-factor Table 8 -1 Surface Type Size of area U-factor R-values (width x height = ff') a) Walls 0.06 b) Ceiling (**Assume the ceiling area is the same as rectangular floor area, A=L x W) 0.025 c) Total window x 8 ea (argon-filled, double glazed for all windows) 0.35 d) Total door (insulated steel entry doors) x 2ea 0.20

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Project Management Techniques

The guideways or the roadways that are undertaken to perform a project efficiently and all the tools required to accomplish the task are the general outlines for project management techniques.

Question

Hello, I am having trouble with this homework assignment. I have attached snips

Calculation of Conduction Heat Loss
Unit: BTUS/hours
Area of surface type
R value of surface type
x (inside °F – outside °F)
Hv = Heat loss (Btus/hour) =
Shortened the formula looks like this Hv = (A/R) * AT
i.e) Surface type: window, door, ceiling or wall
Home dimensions and Configuration
30
3
30
60
Figure 1 House dimension
House dimension: Figure 1 is showing front and left side of the house. Assume the house is symmetrical, thus, front
& back, and left &right sides of the house are the same.
Activa
Go to Se

Window insulation: U-factor and R-value:
U-factor measures how well a product prevents heat from escaping a home or building (thermal conductivity). U-factor
ratings generally fall between 0.15 and 1.20. (See more at: http://www.nfrc.org/windowratings/Energy-
ratings.html#sthash.EUkrrint.dpuf) A lower U-factor means a better-insulating window.
The more common term R-value refers to the resistance of the window to heat conduction, and it is the inverse of the U-
factor (that is, R-value = 1/U-factor). Better windows have high R-values and low U-factors.
Determine all surface type of areas in Table 8-1 from the house in figure 1 and calculate R-values with the given U-factor.
Table 8 -1
Surface Type
Size of area
U-factor R-values
(width x height = ft)
a) Walls
0.06
b) Ceiling (**Assume the ceiling area is the same as rectangular floor
area, A-L x W)
0.025
c) Total window x 8 ea
(argon-filled, double glazed for all windows)
0.35
d) Total door (insulated steel entry doors) x 2ea
0.20

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