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1) 20N/m 60 N/m 4 m 2 m 2)

1) 20N/m 60 N/m 4 m 2 m 2)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Can you please answer the questions below 

1) 60 N/m 20N/m 4 m 2 m 2) 200N/m 80 N/m 6 т 3) 300 D/ft 2 ft 4 ft 4) 300 sin (-) N 6 ft 3 ft
Transcribed Image Text:1) 60 N/m 20N/m 4 m 2 m 2) 200N/m 80 N/m 6 т 3) 300 D/ft 2 ft 4 ft 4) 300 sin (-) N 6 ft 3 ft
Homework Week 2 The book doesn't quite present this topic the way I want, or the way I think is simplest to understand. These problems are focused on working through distributed load problems the way I think is simplest. For each of the problems below: a) Draw a sketch where you replace the distributed loading with point load/loads that act at the centroid of the load/loads b) Find the total force of the point loads c) Find the total moment of the point loads about the left side of the beam For the record, the book tends to go a few steps further, and asks you to replace the distributed load with a single point force For example, if the problem was 40N/m 20N/m 2 т 3 т You could sketch 100 N 20N 2.5 m т And find the total force to be -(20N + 100N) = -120N And the total moment to be -20N (m) – 100N(2.5m) = -263 Nm
Transcribed Image Text:Homework Week 2 The book doesn't quite present this topic the way I want, or the way I think is simplest to understand. These problems are focused on working through distributed load problems the way I think is simplest. For each of the problems below: a) Draw a sketch where you replace the distributed loading with point load/loads that act at the centroid of the load/loads b) Find the total force of the point loads c) Find the total moment of the point loads about the left side of the beam For the record, the book tends to go a few steps further, and asks you to replace the distributed load with a single point force For example, if the problem was 40N/m 20N/m 2 т 3 т You could sketch 100 N 20N 2.5 m т And find the total force to be -(20N + 100N) = -120N And the total moment to be -20N (m) – 100N(2.5m) = -263 Nm
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