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U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is -kt the age of the rock? C=Co e +693 -693 -10 Ty2= K= = 1.54 X10

U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is -kt the age of the rock? C=Co e +693 -693 -10 Ty2= K= = 1.54 X10

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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**Question 2 (20 pts)** The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is \(4.5 \times 10^9\) years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock? \[ C = C_0 e^{-kt} \] \[ T_{1/2} = \frac{0.693}{k} \] \[ k = \frac{0.693}{4.5 \times 10^9} = 1.54 \times 10^{-10} \]
Transcribed Image Text:**Question 2 (20 pts)** The decay of U-238 to Pb-206 can be used to estimate the age of inorganic matter. The half-life of U-238 is \(4.5 \times 10^9\) years. In a particular rock sample, the ratio of the numbers of Pb-206 to U-238 atoms is 0.66. Assume all of the Pb-206 present is due to the decay of U-238. What is the age of the rock? \[ C = C_0 e^{-kt} \] \[ T_{1/2} = \frac{0.693}{k} \] \[ k = \frac{0.693}{4.5 \times 10^9} = 1.54 \times 10^{-10} \]
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