Type your answers in all of the blanks and submit If a solution containing 58 g of mercury(1I) nitrate is allowed to react completely with a solution containing 16.642 g of sodium sulfate according to the equation below: Hg(NO3)2(aq) + Na,SO.(aq) + 2NANO3(aq) + HgSO4(s) How many grams of solid precipitate will be formed if the reaction has a 100% yield? Solid precipitate = Type your answer here Tramc

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If a solution containing 58 g of mercury(II) nitrate is allowed to react completely with a solution containing 16.642 g of
sodium sulfate according to the equation below:
Hg(NO3)2(aq) + Na,SO.(aq) → 2NANO3(aq) + HgSO,(s)
How many grams of solid precipitate will be formed if the reaction has a 100% yieldZ
Solid precipitate =
Type your answer here
grams
How many grams of the excess reagent will remain after the reaction?
Excess reagent remaining =
Type your answerhere
%3D
grams
If the reaction has only an 80% yield, how many grams of solid precipitate will be formed?
Solid precipitate =
Type your answerhere
grams
Transcribed Image Text:Type your answers in all of the blanks and submit If a solution containing 58 g of mercury(II) nitrate is allowed to react completely with a solution containing 16.642 g of sodium sulfate according to the equation below: Hg(NO3)2(aq) + Na,SO.(aq) → 2NANO3(aq) + HgSO,(s) How many grams of solid precipitate will be formed if the reaction has a 100% yieldZ Solid precipitate = Type your answer here grams How many grams of the excess reagent will remain after the reaction? Excess reagent remaining = Type your answerhere %3D grams If the reaction has only an 80% yield, how many grams of solid precipitate will be formed? Solid precipitate = Type your answerhere grams
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