Someone plz answer this my 10th time trying to get it right. **Problem: Magnetic Field Due to Parallel Wires**Two wires each carry 10.0 A of current (*in opposite directions*) and are 2.10 mm apart. What is the magnetic field 33.0 cm away at point P, in the plane of the wires? If the net field is into the page, enter a negative value.### Diagram Explanation:- Two parallel lines represent the wires. - The left wire has a current direction into the page.- The right wire has a current direction out of the page.- The wires are 2.10 mm apart, represented by the label "X mm".- A point P is located below the wires, a distance "Y cm" away. - \( X = 2.10 \) mm - \( Y = 33.0 \) cm### Solution:The magnetic field at point P is calculated due to these two wires.**Result:**\[ 2.4 \times 10^{-7} \, \text{T} \](Note: The “×” symbol in the image indicates multiplication, and the “T” stands for Tesla, the unit of magnetic field strength.)

Given that:- Current in each line =10A (in opposite directions)

Two wires each carry 10.0 A of current (in opposite directions) and are 2.10 mm apart. What is the magnetic field 33.0 cm away at point P, in the plane of the wires? If the net field is into the page, enter a negative value. X mm Yem where X= 2.10 mm and Y= 33.0 cm. 2.4e-7 T.

Two wires each carry 10.0 A of current (in opposite directions) and are 2.10 mm apart. What is the magnetic field 33.0 cm away at point P, in the plane of the wires? If the net field is into the page, enter a negative value. X mm Yem where X= 2.10 mm and Y= 33.0 cm. 2.4e-7 T.

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Magnetic Fields

Section: Chapter Questions

Problem 3P: Find the direction of the magnetic field acting on a positively charged particle moving in the...

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