Two vectors have the following magnitude, A = 7.2 m and B = 7.8 m. Their vector product is: A⨯B = -4.7 m i + 11.4 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use
Two vectors have the following magnitude, A = 7.2 m and B = 7.8 m. Their vector product is: A⨯B = -4.7 m i + 11.4 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter9: Energy In Nonisolated Systems
Section: Chapter Questions
Problem 14PQ
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Two vectors have the following magnitude, A = 7.2 m and B = 7.8 m. Their vector product is:
A⨯B = -4.7 m i + 11.4 m k.
What is the angle (in degrees) between the vectors A and B?
Hint: Use
|A⨯B| = AB sin(θ)
(please don't round off any number)
![Two vectors have the following magnitude, A = 7.2 m and B = 7.8 m. Their vector product is:
AxB = -4.7 m i+ 11.4 m k.
What is the angle (in degrees) between the vectors A and B?
Hint: Use
|AxB|
= AB sin(0)
Note: Bold face letters represents a vector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a57de1e-b5ef-46c0-96ee-9dd1ae84c474%2Faa016935-a13c-40c8-8126-1f35ea47e902%2Faknks6l_processed.png&w=3840&q=75)
Transcribed Image Text:Two vectors have the following magnitude, A = 7.2 m and B = 7.8 m. Their vector product is:
AxB = -4.7 m i+ 11.4 m k.
What is the angle (in degrees) between the vectors A and B?
Hint: Use
|AxB|
= AB sin(0)
Note: Bold face letters represents a vector.
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