QUESTION 2Two vectors have the following magnitude, A = 11.8 m and B = 6.8 m. Their vector product is:AxB = -2.3 mi+11.5 m k.What is the angle (in degrees) between the vectors A and B?Hint: Use|AxB| = AB sin(e)Note: Bold face letters represents a vector.

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Two vectors have the following magnitude, A = 11.8 m and B = 6.8 m. Their vector product is: A.B = -2.3 mi+11.5 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A.B| = AB sin(0) Note: Bold face letters represents a vector.

Two vectors have the following magnitude, A = 11.8 m and B = 6.8 m. Their vector product is: A.B = -2.3 mi+11.5 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A.B| = AB sin(0) Note: Bold face letters represents a vector.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Angular Momentum

Section: Chapter Questions

Problem 11.6P

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BOLD THE FACE LETTERS THAT REPRESENTS A VECTOR