Two vectors have the following magnitude, A = 14.2 m and B = 5 m. Their vector product is: AxB = -2.8 m i+ 5.9 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |AxB| = AB sin(0) Note: Bold face letters represents a vector.
Two vectors have the following magnitude, A = 14.2 m and B = 5 m. Their vector product is: AxB = -2.8 m i+ 5.9 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |AxB| = AB sin(0) Note: Bold face letters represents a vector.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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BOLD THE FACE LETTERS THAT REPRESENTS A VECTOR
![Two vectors have the following magnitude, A = 14.2 m and B = 5 m. Their vector product is:
AxB = -2.8 m i + 5.9 m k.
What is the angle (in degrees) between the vectors A and B?
Hint: Use
|AxB|
= AB sin(0)
Note: Bold face letters represents a vector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff4aa893f-a74e-479d-9520-44bc27abcf80%2F4c17611f-1a89-4160-be6d-0ed4e7fbcd05%2F31ho7se_processed.png&w=3840&q=75)
Transcribed Image Text:Two vectors have the following magnitude, A = 14.2 m and B = 5 m. Their vector product is:
AxB = -2.8 m i + 5.9 m k.
What is the angle (in degrees) between the vectors A and B?
Hint: Use
|AxB|
= AB sin(0)
Note: Bold face letters represents a vector.
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