Two tangents of a simple curve have an azimuth of 250⁰15’ and 280⁰15’ respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
Two tangents of a simple curve have an azimuth of 250⁰15’ and 280⁰15’ respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Two tangents of a simple curve have
an azimuth of 250⁰15’ and 280⁰15’
respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
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