Two tangents of a simple curve have an azimuth of 250⁰15’ and 280⁰15’ respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
Two tangents of a simple curve have an azimuth of 250⁰15’ and 280⁰15’ respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter15: Geometric Design Of Highway Facilities
Section: Chapter Questions
Problem 7P
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Two tangents of a simple curve have
an azimuth of 250⁰15’ and 280⁰15’
respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
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