Two tangents intersecting at V with azimuths of 255⁰12’ and 281⁰24’ respectively are joined by a 4⁰ simple curve. Without changing the direction of the two tangents, it is required to shorten the curve to one-fourth of the original length of the curve from the beginning of the curve. The stationing of the vertex of the new curve is at 10+545. Determine the following:  Tangent of the new curve. Stationing of the beginning of the curve. Stationing of the end of the curve. Long chord of the new curve

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