Two tangents adjacent to each other having bearings N65º30'E and S85°10'E meetat station 11+157.98. If the radius of the simple curve connecting the two tangentsis 249.17m, determine the following:Tangent DistanceLong ChordMiddle ChordExternal ChordDegree of Curve using Arc DefinitionLength of CurveStationing of PT

Answered: Image /qna-images/answer/a2f35b41-7e8a-4c44-a374-b0f8db0b40b3.jpg

Answered: Two tangents adjacent to each other…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the intermediate chord length (ft) (i.e. the straight line distance between two sequential full stations)?
The tangents of a simple curve have bearings of N 20° E and N 80° E. respectively. The radius of the curve is 200m. Compute the external distance of the curve. Select the correct response: 157.07 m 30.94 m 149.71 m 175.07 m
A simple curve connects teo tangents AB and BC with bearing N84E and S653, respectively. If the stationing of the vertex is 4,362 and the stationing of PC is 4,285 . Determine the ff: A) the radius of the curve B) the external distance;C) The middle ordinate D) chord distance E) the length of the curve
K8
Two tangents converge at an angle 26.7 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 134.02 meters. What is the value of the total curve in meters if the bearing of the common tangent is S 35.6 E. Take into consideration that the length of the first tangent is one third the length of the second tangent. Station PC is at Sta 10+620.
Please also show the diagram/graph of curve.
Two tangents adjacent to each other having bearings N 65 E and S 81 E meet at station 11+150. If the radius of the simple curve connecting these two tangents is 251 m, determine the following A. Tangent Distance B. Length of curve C. Station of PT
Two tangents intersect at station 26+050. A compound curve laid on their tangents has tne following data: I1 = 31deg I2 = 36deg D1 = 3 deg D2 = 5 deg determine: a) The stationing of the PC (format: 00+000.00) b) The stationing of the PT (format: 00+000.00) c) Total length of the common tangent **2 DECIMAL PLACES ONLY**
No. 7 only
A simple curve connects two tangent roads AB and BC with bearings N82º40’E and S67º40’E, respectively. If the chainage (or stationing) of the point of intersection of the two tangents is 4+337.42 and the radius of the curve is 300m, determine the following: (Show illustration) Tangent distance External distance Middle Ordinate Versine Long Chord Length of the curve
SITUATION. The long chord of a compound curve is equal to 250 meters. The PC this curve is at STA 10+000 and the P.C.C. is at 10+139.393. The angle that the chord connecting the P.C. and P.C.C makes with the tangent passing through P.C. is equal to 4°. Assuming that the common tangent is parallel to the long chord, Zoom image Evaluate the radius R1 782.1 m O524.2 m O832.6 m 998.3 m

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