Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Two strings, A and B, have respective mass densities µA and µB respectively. The linear mass density, µB, of string-B is nine times that of string-A (µB = 9µA). If both strings %3D have the same fundamental frequency when kept at the same tension, then the ratio of their lengths LA / LB is equal to: O 1/3 O 1/9

Two strings, A and B, have respective mass densities µA and µB respectively. The linear mass density, µB, of string-B is nine times that of string-A (µB = 9µA). If both strings %3D have the same fundamental frequency when kept at the same tension, then the ratio of their lengths LA / LB is equal to: O 1/3 O 1/9

icon
Related questions
Question
i need the answer quickly
Two strings, A and B, have respective mass densities µA and µB respectively. The linear mass density, µB, of string-B is nine times that of string-A (uB = 9µA). If both strings %3D have the same fundamental frequency when kept at the same tension, then the ratio of their lengths LA/ LB is equal to: 1/3 1/9 9.
Transcribed Image Text:Two strings, A and B, have respective mass densities µA and µB respectively. The linear mass density, µB, of string-B is nine times that of string-A (uB = 9µA). If both strings %3D have the same fundamental frequency when kept at the same tension, then the ratio of their lengths LA/ LB is equal to: 1/3 1/9 9.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer