Two speakers placed a distance x apart emit the same frequency. An observer stands directly in front of one of the speakers as shown. If x is set to be 1.5 m and the speakers are operating in phase with each other, find values for the two lowest frequencies for which the observer hears destructive interference (intensity minima). 우 2.0 m
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- i ock 10. The figure shows two loudspeakers (A) and (B), and a point (C) where a listener is positioned. The speakers vibrate out of phase and are playing a 72.0 Hz tone. The speed of sound is 338 m/s. The listener at point (C) hears the second constructive interference at a distance 6.00 m as measured from speaker (A). What is the separation (d) between the two speakers? esc ! 1 Q A ← 1 N NO 2 W S . m # 3 Xx H control option command с E D $ 4 с R FL se i % G Search or type URL 5 V ZEEL!! ZEEL! ZEEI!! zee!! zelf ze T G) 3133 jj1332 jj1332 jj13 jj1332 jj13 MacBook Pro 6 B Y 232332111332 jj1332 jj1332 jj13324 & v lo H 7 11332 jj1332 1133211332 jj332 jj1332, jj U N 00 * 8 J 1332 jj1332 jj1332 jjl332 jj242-1 I M ✪ ( 9 o K O : 7 I ; Ÿ option { [ ? = 1 I A O } ] delete I VTwo speakers sit 4.0m apart. Each is playing the same pure tone, of a single frequency sinusoidal sound wave. For simplicity, we can place these on the y-axis at y = +2.0m and at y = -2.0m. You stand on the centerline between the speakers, and 10.0m in front of them (this would be at y = 0m, x = 10.0m) At this location, you hear maximum intensity sound, a.k.a. constructive interference. You then walk in the +y direction until you hear a minimum intensity of sound, a.k.a. destructive interference. This happens when you reach y = 2.5m. (Your coordinates would now be x = 10.0, y = 2.5.) Interference is based on path length differences form different sources to the same detection point. Identify the paths from the two different speakers to the first observation point (10,0). How long is each of these paths?Two loudspeakers in a plane are 2.0 m apart and in phase with each other. Both emit 700 Hz sound waves into a room where the speed of sound is 341 m/s. A listener stands 5.0 m in front of the loudspeakers and 2.0 m to one side of the center. a)ls the interference at this point maximum constructive, maximum destructive, or in between? b)How will the situation differ if the loudspeakers are out of phase? Step 1: SKETCH the situation. Step 2: Draw the distance r₁ from source 1 to the point and the distance r₂ from source 2 to the point Step 3: Find 1 and 2, then calculate Ar. Step 4: Find the wavelength Step 5:Find the phase difference at that point.
- Two speakers are against a wall emitting a sound at 767 Hz, 14 m apart, and facing each other. You are standing against the wall in between the speakers. Use 344ms for the speed of sound in air. A) What is the closest distance that you can be from the speaker on the left at which you exprerience total destructive interference, and the sound from the speakers cancel out? B) What is the closest distance that you can be from the speaker on the left at which you experrience total constructive interference, and the sound intensity is doubled?I need help on the last two parts. Thank you!Point P is at some distance away from the center between two speakers. Both speakers are producing the same frequency and are in phase with each other. What is the smallest frequency value for which there will be no sound at Point P?
- The following graph shows the superposition of two identical sound waves that are out of phase. Sketch the resulting sound wave on the graph and identify the type of interference. What does this mean for the listener hearing these two waves simultaneously? mo 2.38 3.30 AWhen two sources located at different positions produce the same pure tone, the human ear will often hear one sound that is equal to the sum of the individual tones. Since the sources are at different locations, they will have different phase angles p. If two speakers located at different positions produce pure tones 元 P, =A, sin (2uft + 1) and P, = A2 sin (2nft + dp2) , where - s41,.427, then the resulting tone heard by a listener can be written as P = A sin (2nft + 4), where A, sin 4, + A, sin p2 4 = arctan (A, cos 4, + A, cos 42)² + (A, sin d, + A2 sin 2) 2 . Complete parts a and b. and A = 1 A, cos , + A2 cos 42 (a) Calculate A and p if A, = 0.0009, , =0.057, A2=0.004, and p2 = 0.68. Also find an expression for P = A sin (2xft + 4p) if f= 220. A = (Do not round until the final answer. Then round to five decimal places as needed.) (Do not round until the final answer. Then round to five decimal places as needed.) Find an expression for P = A sin (2xft + 4) if f= 220. P= (Use…Item 12 IP Two violinists, one directly behind the other, play for a listener directly in front of them. Both violinists sound concert A (440 Hz). Part A What is the smallest separation between the violinists that will produce destructive interference for the listener? d = Submit Part B —| ΑΣΦ Request Answer increases Submit Does this smallest separation increase or decrease if the violinists produce a note with a higher frequency? decreases ? Request Answer m
- The sound pressure level at 250 Hz is 50 dB in one room and in 30 dB in the other. The surface area of the wall between them is 15 m2. The total amount of absorption at 250 Hz in the room with the lower noise level is 20 Sabines. What is the sound reduction index of the separating partition at 250 Hz:a. 20.0 dBb. 17.5 dBc. 18.8 dBd. 44.8 dBTwo speakers are a distance d = 19.95m apart and emitting in-phase sound of frequency f = 55Hz. The sound is traveling at a speed of v= 339.8m/s. If a person starts by standing at one of the speakers and walks towards the other one, what is the shortest distance they can walk to find a point in which they hear destructive interference? 6.5 m