1. Two small speakers S are positioned a distance 0.75 m from each other. The two speakers – that are in phase with each other – are each emitting a constant 2500 Hz in a room with a temperature of 20°C. A student stands at point P, which is 5.0 m from the midpoint between the speakers hears the maximum. The student moves a distance Y to point Q and notices that the sound intensity has decreased to a minimum. Note: The speed of sound in air is given by the formula V = 331 + 0.6T. -5.0m What is the shortest distance that the student could have moveď? 0.75 If the student continues walking from point Q, then how far will he walk to hear

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1. Two small speakers S are positioned a distance 0.75 m from each other. The two speakers – that are in phase
with each other – are each emitting a constant 2500 Hz in a room with a temperature of 20°C. A student stands
at point P, which is 5.0 m from the midpoint between the speakers hears the maximum. The student moves a
distance Y to point Q and notices that the sound intensity has decreased to a minimum.
Note: The speed of sound in air is given by the formula V = 331 + 0.6T.
-5.0 m
What is the shortest distance that the student could have moved?
0.75 m
If the student continues walking from point Q, then how far will he walk to hear
the minimum sound again?
Transcribed Image Text:1. Two small speakers S are positioned a distance 0.75 m from each other. The two speakers – that are in phase with each other – are each emitting a constant 2500 Hz in a room with a temperature of 20°C. A student stands at point P, which is 5.0 m from the midpoint between the speakers hears the maximum. The student moves a distance Y to point Q and notices that the sound intensity has decreased to a minimum. Note: The speed of sound in air is given by the formula V = 331 + 0.6T. -5.0 m What is the shortest distance that the student could have moved? 0.75 m If the student continues walking from point Q, then how far will he walk to hear the minimum sound again?
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