Two small balls with charges q₁ = 8.8 µC and q = -16.1 µC are separated by a distance d = 5.0 cm. Calculate the electric flux passing through th following three surfaces: $1 = A spherical surface of radius 2.1 cm centered on the first charge. -8.24 * 10⁹ A spherical surface of radius 14 cm centered on the second charge. A spherical surface of radius 1.4 cm centered at the midpoint of a line connecting them.

Two small balls with charges q₁ = 8.8 µC and q = -16.1 µC are separated by a distance d = 5.0 cm. Calculate the electric flux passing through th following three surfaces: $1 = A spherical surface of radius 2.1 cm centered on the first charge. -8.24 * 10⁹ A spherical surface of radius 14 cm centered on the second charge. A spherical surface of radius 1.4 cm centered at the midpoint of a line connecting them.

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Two small balls with charges q1 = 8.8 µC and q = -16.1 µC are separated by a distance d = 5.0 cm. Calculate the electric flux passing through the
following three surfaces:
P₁
A spherical surface of radius 2.1 cm centered on the first charge.
-8.24 * 109
A spherical surface of radius 14 cm centered on the second charge.
A spherical surface of radius 1.4 cm centered at the midpoint of a line connecting them.

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Step 2: (a) Flux passing through a spherical surface of R=2.1 cm centered on the first charge:

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Step 3: (b) Flux passing through a spherical surface of R=14 cm centered on the first charge:

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Step 4: (c) Flux passing through a spherical surface of R=1.4 cm centered on the midpoint.

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