Two slits are illuminated with green light (2 = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the average intensity 50% of the intensity of the central maximum? a. b. 3 c. d. 4 e. 0.4 ANS: D PTS: 3 DIF: Challenging
Two slits are illuminated with green light (2 = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the average intensity 50% of the intensity of the central maximum? a. b. 3 c. d. 4 e. 0.4 ANS: D PTS: 3 DIF: Challenging
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I already know the answer to this practice problem, and it is shown is the image. I do not know how to get to the answer though, so seeing the steps and equations would be much appreciated.
Transcribed Image Text:Two slits are illuminated with green light (2 = 540 nm). The slits are 0.05 mm apart and the distance to the screen is 1.5 m. At what distance (in mm) from the central maximum on the screen is the
average intensity 50% of the intensity of the central maximum?
a.
b. 3
c.
d. 4
e. 0.4
ANS: D
PTS: 3
DIF: Challenging
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