Two resistors R1 and R2 are connected in parallel. Let R1=( 50 ±0.5)N and R2=( 100 + 1 :)2. Determine the error in the parallel equivalent resistance Rp and calculate Rp±ARp . R,R, R, R, + R,
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- With eh following values, what is the current through R1, in A? Use positive for to the right, and negative for to the left. V1 = 10.9 V V2 = 16.1 V R1 = 26 Ω R2 = 77 ΩThree resistors, R₁ = 232, R₂=3502, and R,=4552, are connected to a capacitor of capacitance C=32μF and a battery with emf 8=14V as shown in the figure below. The capacitor is initially uncharged when the switch is closed at t-0. Determine the current running on R, on the capacitor at r=0. Express your answer in units mA using zero decimal places. S w ++ R₁ www C ww R3If R is the total resistance of three resistors, connected in parallel, with resistances R₁, R₂, R3, then 1/2 = 1/₂+1/2+1/3 R R₁ If the resistances are measured in ohms as R₁ = 64, R₂ = 82, and R3 = 42, with a possible error of 0.5% in each case, estimate the maximum error in the calculated value of R. (Round your answer to three decimal places.) .005 x 22
- Problem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACEDescribe your approach to determining the distance between the electron and proton in an atom if the potential energy U of the electron is known to be 14 eV. а. Use the law of conservation of energy. b. Use Coulomb's law. С. Use the definition of electrostatic potential energy U of one point charge q at position r in the presence of an electric potential. d. Use Newton's second law.A capacitor of capacitance C = 1 μF has been charged so that the potential difference between its plates is V0 = 295 V. The capacitor is then connected to a resistor of resistance R = 11.5 kΩ. The switch S is closed, and the capacitor begins to discharge. Calculate the time T in s after which the charge on the capacitor has decreased to one fourth its maximum value.
- A 25-turn circular coil has radius of r = 3 [cm] and a resistance of R = 10 [Q]. The coil is in a uniform magnetic field of 0.46 [T] that is perpendicular to the plane of the coil. a. magnetic flux? What is the value of the b. What is the value of the induced emf and the induced current in the coil? lemf| = [V] I = [A] Now, the value of the magnetic field is increasing from 0.46 [T] to 2.1 [T] in At = 1.4 [s]. C. emf? lemf| I = What is the value of the induced [V] d. current in the coil? [A] What is the value of the inducedYou have the circiut below with V=60 V, C-575 μF, and R-310 ks2. You move the switch to the left position and let the capacitor become fully charged. With the capacitor fully charged, you flip the switch to the right so that the capacitor is now in a circuit with resistor R. After a time 178.25 s, the charge on the capacitor has decreased by a factor of 2.7. C R V What is the average current going through the resistor in that time? Number A. What is the average power dissipated through the resitor in this time? Number W.