Two positive thin lenses have a focal length of 40 cm and 60 cm respectively and both lenses are 20 cm apart. Where an object should be placed so that its image is 45 cm behind the second lens. Determine the location of the main points.
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Two positive thin lenses have a focal length of 40 cm and 60 cm respectively and both lenses are 20 cm apart. Where an object should be placed so that its image is 45 cm behind the second lens. Determine the location of the main points.
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- An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.200 m in front of a diverging lens. The focal length of the lens is -0.27 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? m4.To measure the focal length of a diverging lens, a converging lens is placed in contact with it as shown to the right. The sun's focused by this Image point made by first lens (object point for second lens) are rays combination at a point 28.5 cm behind Image made by second lens the lenses. If the converging lens has a focal length fc of 16 cm, what is the focal length of the diverging lens? (final image) fc -fr =28.5 cmAn object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.140 m in front of a diverging lens. The focal length of the lens is -0.25 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? m
- A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualPlease don't provide handwritten solution.... A diverging lens with f = -37.5 cm is placed 15.0 cm behind a converging lens with f = 21.0 cm .Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.For safety reasons, you install a rear-window lens with a -0.299 m focal length in your van. Before putting the van in reverse, you look through the lens and see the image of a person who appears to be 0.339 m tall and 0.243 m behind the van. Determine the following. (a) actual distance of the person behind the van m (b) height of the person
- A 1.00-cm-high object is placed 4.35 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position |-7.8 X cm in front of the second lens v height cmA nearsighted person has a far point of 25.3cm and is prescribed contact lenses to correct her vision. What lens strength (a.k.a., lens power), in Diopters, should be prescribed? Give your answer using the usual convention of positive values for converging lenses and negative values for diverging lenses.A converging lens has a focal length of 20.0 cm. Construct accurate ray diagrams for object distances of (i) 60.0 cm and (ii) 6.67 cm. (a) From your ray diagrams, determine the location of each image. Image (i) distance = Image (ii) distance =