4.To measure the focal length of a diverging lens, a converging lens is placed in contact with it as shown to the right. The sun's are focused by this rays combination at a point 28.5 cm behind the lenses. If the converging lens has a focal length fc of 16 cm, what is the focal length of the diverging lens?
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- An object is 25 centimeters from a converging lens with a focal length of +35 centimeters. Where is the image located and what is the magnification of the image? Is the image upright or inverted? Is the image real or virtual? Provide an accurate ray diagram.9. A diverging lens (f, = -10.5 cm) is located 54.0 cm to the left of a converging lens (f2 = 20.0 cm). A 2.5-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens (including proper algebraic sign). cm6. A convex lens is held over a piece of paper outdoors on a sunny day. When the paper is held 22 cm below the lens,the sunlight is focused on the paper and the paper ignites. What is the focal length of the lens?
- 10a: Please help answer this ASAP7. A lighted candle is placed 40.0 cm in front of a diverging lens. The light passes through the diverging lens and on to a converging lens (f = 10.0 cm) that is placed 9.00 cm from the diverging lens. The final image is real, inverted, and 35.0 cm beyond the converging lens. Find the focal length of the diverging lens. cm 0 ssf6 ssf60 ssf 60 ssf607 ssf60HW8 Q10 A magnifying glass is a single convex lens with a focal length of f= 13.0 cm. What is the angular magnification when this lens forms a (virtual) image at −∞? How far from the object should the lens be held? What is the angular magnification when this lens forms a (virtual) image at the person's near point (assumed to be 25 cm)? How far from the object should the lens be held in this case?
- 1. A homeowner wishes to mount a floodlight on a wall of a swimming pool underwater so as to provide the maximum illumination of the surface of the pool for use at night. At what angle with respect to the wall would the light be pointed? The answer is 46 degrees. 2. In a slide projector, a slide is positioned 0.102 meters from a converging lens that has a focal length of 0.1 meters. At what distance from the lens must the screen be placed so that the image of the slide will be in focus? The answer is 5.1m 3. Compute the magnification for the slide projector in Q2. The answer is -50X= 20.0 cm and fB 25.0 cm, Q3: A two-lens system. Two converging lenses, A and B, with focal lengths f are placed 80.0 cm apart, as shown in Figure. An object is placed 60.0 cm in front of the first lens. Determine (a) the position, and (b) the magnification, of the final image formed by the combination of the two lenses. F A A B ff TI TI பட B =Spherical aberration is due to light rays O a. passing through the outer portions of a lens not focusing at the same point as rays that pass through the center O b. of different wavelength not focusing at the same point O C. passing through the lens in the vertical direction not focusing at the same point as rays passing through the lens in the horizontal direction O d. passing through the outer portions of a lens being absorbed more than rays that pass through the center
- 2. An object is placed 50.cm in front of a converging lens and then 15.5cm in front of a diverging lens. Both lenses have a focal length of 12.0cm. For both cases, find the image distance.2. A diverging lens (focal length f₁ = -16.0 cm) is placed a distance of d = 32.0 cm to the left of a converging lens (focal length f2 = 8.00 cm). An object is placed p₁ = 20.0 cm to the left of the diverging lens and has a height of h 1 13.0 cm. (a) Where is the image formed by the diverging lens (i.e. what is qi)? What is this image's height and is it upright or inverted? Does this image become a real or virtual object for the converging lens? (b) Where is the final image (i.e. what is q2)? Is it real or virtual? What is this image's height and is it upright or inverted? (c) On the figure below, draw a ray diagram of this situation. fi f2 f22. Show that the minimum distance between a real object and its real image given by a convergent lens of focal length f is 4f. Get q as a function of p from 1/p + 1/q = 1/f. Take the derivative of s = p +q to find the value of p for which s is minimum.