please answer all parts of questionthere is an equation sheet providedpart a) is an image and part b) is down belowb) Say that you replaced the +? charge on the top with a negative charge of equal magnitude (−?). How would the net force on ?# now compare to the net force from before? You can answer without explicitly calculating this new force, but make sure you discuss both the direction and magnitude of the force. Explain your reasoning. Two positive point charges +Q are fixed in place a distance b from anegative point charge qo, as shown.A student writes the following expressionfor the magnitude of the net electric force on qo:|EF|=2kQqob²b-90-$30030°30°b+Q+QIs this expression correct? If it is, explain why it is a valid expression. If it is not, explain any errorsand how to correct them, then write a correct expression for the net force. |Epc|=W = F - Ax = |F||Ax| cosMathematical Relations:√2sin (0)kQp²45°145°0HkQq|²| = =p21| Ēroa| = 222kQErodrLΔΡΕ =Vpc=cos(0)=qAVF = qËEWextkQAHH² = A² + 0²30⁰==▬▬▬▬2kλ√3/2r|Ē| := AE = AKE + APE + ··tan (0)==Vsheet = Ex60°p = Qd0A|Esheet | ==AVAxSpecial Triangles:Note that you can use these to determine the sine/cosine of the angles, e.g. cos(45) = 1/√2 = √2/21/22лkQA= 2лko0537⁰Wint = -APEH4A53°3

Answered: Two positive point charges +Q are fixed…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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please answer all parts of question

there is an equation sheet provided

part a) is an image and part b) is down below

b) Say that you replaced the +? charge on the top with a negative charge of equal
magnitude (−?). How would the net force on ?# now compare to the net force from before? You
can answer without explicitly calculating this new force, but make sure you discuss both the
direction and magnitude of the force. Explain your reasoning.

Two positive point charges +Q are fixed in place a distance b from a
negative point charge qo, as shown.
A student writes the following expression
for the magnitude of the net electric force on qo:
|EF|
=
2kQqo
b²
b
-90-$300
30°
30°
b
+Q
+Q
Is this expression correct? If it is, explain why it is a valid expression. If it is not, explain any errors
and how to correct them, then write a correct expression for the net force.

|Epc|=
W = F - Ax = |F||Ax| cos
Mathematical Relations:
√2
sin (0)
kQ
p²
45°
1
45°
0
H
kQq
|²| = =
p2
1
| Ēroa| = 22
2kQ
Erod
rL
ΔΡΕ =
Vpc
=
cos(0)
=qAV
F = qË
EWext
kQ
A
H
H² = A² + 0²
30⁰
==▬▬▬▬
2kλ
√3/2
r
|Ē| :
= AE = AKE + APE + ··
tan (0)
=
=
Vsheet = Ex
60°
p = Qd
0
A
|Esheet | =
=
AV
Ax
Special Triangles:
Note that you can use these to determine the sine/cosine of the angles, e.g. cos(45) = 1/√2 = √2/2
1/2
2лkQ
A
= 2лko
0
5
37⁰
Wint = -APE
H
4
A
53°
3

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