A. The force exerted on a small uniform conducting sphere of charge ql at a distance d from another sphere of charge q2 is + F. If we triple the charge of the sphere q1 and that we reduce the distance by half between q1 and q2, the new force will be: I. Of +8 F II. +12 F III. Of + F 2 IV. Of-F Explanations: B) Two charges are placed as shown below. Calculate the net electric field at point X. 9₁=+3,2x10 °C 92=-6,4×10 °C 15 cm X I 27 cm

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Chapter1: Units, Trigonometry. And Vectors
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A. The force exerted on a small uniform conducting sphere of charge ql at
a distance d from another sphere of charge q2 is + F. If we triple the charge
of the sphere q1 and that we reduce the distance by half between q1 and q2, the
new force will be:
I. Of +8 F
II. +12 F
III. Of + F 2
IV. Of-F
Explanations:
B) Two charges are placed as shown below. Calculate the net electric field at point X.
9₁=+3,2x10 °C
9₂=-6,4×10 °C
15 cm
X
I
27 cm
Transcribed Image Text:A. The force exerted on a small uniform conducting sphere of charge ql at a distance d from another sphere of charge q2 is + F. If we triple the charge of the sphere q1 and that we reduce the distance by half between q1 and q2, the new force will be: I. Of +8 F II. +12 F III. Of + F 2 IV. Of-F Explanations: B) Two charges are placed as shown below. Calculate the net electric field at point X. 9₁=+3,2x10 °C 9₂=-6,4×10 °C 15 cm X I 27 cm
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